GCSE Mathematics

CCEA Higher Tier Revision Space

CCEA Subject Code 2210 Higher Tier: M3+M7 (B–E) or M4+M8 (A*–C) Summer 2026 series
0 of 0 topics completed (0%)

CCEA Specification — At a Glance

Higher Tier students sit two modules. Pick your pathway to filter the revision topics below. Your choice is saved to this device.

Unit M3 — Higher

Module paper · grades B–E
Thu 14 May 2026 · 09:15 · 2 hr
Calculator allowed · prerequisite M1, M2

Unit M4 — Higher

Module paper · grades A*–C (D allowable)
Thu 14 May 2026 · 09:15 · 2 hr
Calculator allowed · prerequisite M1, M2, M3

Unit M7 — Completion

Non-calc + calc · grades B–E
Wed 3 Jun 2026 · 09:15 (non-calc) · 10:45 (calc) · 1 hr 15 each
prerequisite M1–M3, M5, M6

Unit M8 — Completion

Non-calc + calc · grades A*–C (D allowable)
Wed 3 Jun 2026 · 09:15 (non-calc) · 10:45 (calc) · 1 hr 15 each
A* awarded from M4+M8 total · prerequisite M1–M7
Types of Number Both Papers

Understanding different types of numbers and their properties is fundamental to all areas of GCSE Maths.

Number Types
  • Natural numbers: Positive counting numbers: 1, 2, 3, 4, 5, ...
  • Integers: Whole numbers including negatives: ..., -3, -2, -1, 0, 1, 2, 3, ...
  • Rational numbers: Any number that can be written as a fraction p/q where q is not 0. Includes terminating and recurring decimals.
  • Irrational numbers: Cannot be written as a fraction. Decimals are non-terminating and non-repeating. Examples: pi, sqrt(2), sqrt(3).
  • Prime numbers: Numbers with exactly two factors (1 and itself): 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, ...
Factors, Multiples, HCF and LCM
  • Factors: Numbers that divide exactly into another number. Factors of 12: 1, 2, 3, 4, 6, 12
  • Multiples: Results of multiplying a number by integers. Multiples of 5: 5, 10, 15, 20, 25, ...
  • HCF (Highest Common Factor): The largest factor shared by two or more numbers
  • LCM (Lowest Common Multiple): The smallest number that is a multiple of two or more numbers
  • Prime factorisation: Writing a number as a product of prime factors using a factor tree or repeated division
Key Method: Finding HCF and LCM Step 1: Write each number as a product of prime factors
HCF = product of COMMON prime factors (lowest powers)
LCM = product of ALL prime factors (highest powers)
Worked Example: Find the HCF and LCM of 36 and 90
Prime factorisation of 36: 36 = 2 x 18 = 2 x 2 x 9 = 2 x 2 x 3 x 3 = 2^2 x 3^2
Prime factorisation of 90: 90 = 2 x 45 = 2 x 3 x 15 = 2 x 3 x 3 x 5 = 2 x 3^2 x 5
HCF: Take the common primes with lowest powers: 2^1 x 3^2 = 2 x 9 = 18
LCM: Take all primes with highest powers: 2^2 x 3^2 x 5 = 4 x 9 x 5 = 180
HCF = 18, LCM = 180
Quick Check
Find the HCF and LCM of 24 and 60.
24 = 2^3 x 3, 60 = 2^2 x 3 x 5
HCF = 2^2 x 3 = 12
LCM = 2^3 x 3 x 5 = 120

Confusing HCF and LCM. HCF is always smaller or equal to the smaller number. LCM is always larger or equal to the larger number. Remember: HCF uses lowest powers of common factors; LCM uses highest powers of all factors.

You can check your answer: HCF x LCM = product of the two numbers. So 18 x 180 = 3240, and 36 x 90 = 3240. They match!

Fractions, Decimals and Percentages Both Papers

Converting between fractions, decimals and percentages and performing operations with them.

Conversions
  • Fraction to decimal: Divide numerator by denominator. 3/8 = 3 divided by 8 = 0.375
  • Decimal to percentage: Multiply by 100. 0.375 = 37.5%
  • Percentage to fraction: Write over 100 and simplify. 35% = 35/100 = 7/20
  • Recurring decimals to fractions: Use algebra. Let x = 0.333..., then 10x = 3.333..., so 9x = 3, so x = 3/9 = 1/3
Operations with Fractions
Fraction Operations Addition/Subtraction: Find common denominator, then add/subtract numerators
Multiplication: a/b x c/d = (a x c)/(b x d)
Division: a/b / c/d = a/b x d/c (flip and multiply)
Worked Example: Calculate 2/3 + 3/4 - 1/6
Find the LCM of 3, 4 and 6: LCM = 12
Convert each fraction: 2/3 = 8/12, 3/4 = 9/12, 1/6 = 2/12
Calculate: 8/12 + 9/12 - 2/12 = 15/12
Simplify: 15/12 = 5/4 = 1 and 1/4
1 and 1/4 (or 5/4)
Worked Example: Convert 0.454545... to a fraction
Let x = 0.454545... (the recurring block is "45", two digits)
Multiply by 100 (two digits recurring): 100x = 45.454545...
Subtract: 100x - x = 45.4545... - 0.4545... = 45
So 99x = 45, therefore x = 45/99 = 5/11
0.454545... = 5/11

Adding fractions by adding numerators and denominators: 1/3 + 1/4 = 2/7 You must find a common denominator first: 1/3 + 1/4 = 4/12 + 3/12 = 7/12

Quick Check
Convert 0.1666... (where the 6 recurs) to a fraction.
Let x = 0.1666...
10x = 1.666...
100x = 16.666...
100x - 10x = 15
90x = 15
x = 15/90 = 1/6
Ratio and Proportion Both Papers

Ratios compare quantities. Proportion describes how quantities change together.

Simplifying and Using Ratios
  • Simplifying: Divide all parts by their HCF. 12:18 = 2:3
  • Sharing in a ratio: Find total parts, divide amount by total parts, multiply by each part
  • 1:n form: Divide both parts by the first number
  • Combining ratios: Make the shared part equal, then combine
Direct and Inverse Proportion
Proportion Direct proportion: y = kx (as x increases, y increases at same rate)
Inverse proportion: y = k/x (as x increases, y decreases)
k is the constant of proportionality
Worked Example: Share 240 in the ratio 3:5
Find total parts: 3 + 5 = 8 parts
Find one part: 240 / 8 = 30
First share: 3 x 30 = 90
Second share: 5 x 30 = 150
90 and 150 (check: 90 + 150 = 240)

Dividing 240 by 3 and 5 separately to get 80 and 48. You must first find the total number of parts (3+5=8), then divide the total amount by that, then multiply each part.

Always check your ratio answer by adding the parts back together — they should sum to the original total. If the question says "share 240 in the ratio 3:5" and your two answers don't add to 240, something's wrong.

Powers, Roots and Indices Both Papers

Laws of indices, standard form and surds are essential for Higher Tier.

Laws of Indices
Index Laws a^m x a^n = a^(m+n) Multiply: add powers
a^m / a^n = a^(m-n) Divide: subtract powers
(a^m)^n = a^(mn) Power of a power: multiply
a^0 = 1 Anything to the power 0 is 1
a^(-n) = 1/a^n Negative power: reciprocal
a^(1/n) = n-th root of a Fractional power: root
a^(m/n) = (n-th root of a)^m
Standard Form
  • Written as A x 10^n where 1 ≤ A < 10 and n is an integer
  • Large numbers: positive power of 10 (e.g., 3 400 000 = 3.4 x 10^6)
  • Small numbers: negative power of 10 (e.g., 0.00056 = 5.6 x 10^-4)
  • To add/subtract in standard form: convert to ordinary numbers or make powers of 10 equal
Surds
Surd Rules sqrt(a) x sqrt(b) = sqrt(ab)
sqrt(a) / sqrt(b) = sqrt(a/b)
Simplifying: sqrt(12) = sqrt(4 x 3) = 2*sqrt(3)
Rationalising: a/sqrt(b) = a*sqrt(b)/b
Worked Example: Simplify sqrt(75) + sqrt(12)
Simplify sqrt(75): sqrt(75) = sqrt(25 x 3) = 5*sqrt(3)
Simplify sqrt(12): sqrt(12) = sqrt(4 x 3) = 2*sqrt(3)
Add: 5*sqrt(3) + 2*sqrt(3) = 7*sqrt(3)
7 sqrt(3)
Worked Example: Evaluate 27^(2/3)
The denominator of the fraction is the root: cube root of 27 = 3
The numerator of the fraction is the power: 3^2 = 9
27^(2/3) = 9

Thinking that a^(2/3) means "divide by 3 then multiply by 2". a^(2/3) means "cube root first, then square" (or equivalently "square first, then cube root"). The denominator is the root, the numerator is the power.

Quick Check
Simplify: 2^3 x 2^5 / 2^4
2^3 x 2^5 = 2^8
2^8 / 2^4 = 2^4 = 16
Accuracy and Bounds Non-Calculator

Rounding, estimation, and understanding the limits of accuracy in measurements.

Rounding
  • Decimal places (dp): Count digits after the decimal point. 3.146 to 2 dp = 3.15
  • Significant figures (sf): Count from first non-zero digit. 0.003042 to 2 sf = 0.0030
  • Estimation: Round each number to 1 significant figure, then calculate
  • Truncation: Simply cut off digits without rounding (3.147 truncated to 2dp = 3.14)
Upper and Lower Bounds
Bounds If a value is rounded to the nearest unit:
Lower bound = value - half the degree of accuracy
Upper bound = value + half the degree of accuracy

Error interval: lower bound ≤ x < upper bound

Example: 5.3 cm (to 1 dp) means 5.25 ≤ length < 5.35
Worked Example: Bounds calculation for speed
A car travels 120 km (to nearest 10 km) in 2 hours (to nearest hour). Find bounds for speed.
Distance bounds: 115 km ≤ d < 125 km
Time bounds: 1.5 hours ≤ t < 2.5 hours
Maximum speed = max distance / min time: 125 / 1.5 = 83.3 km/h
Minimum speed = min distance / max time: 115 / 2.5 = 46 km/h
Speed is between 46 km/h and 83.3 km/h

For maximum of a/b, using max a / max b. To maximise a fraction, you use the maximum numerator divided by the minimum denominator. To minimise a fraction, use minimum numerator / maximum denominator.

When writing error intervals, remember: the lower bound uses ≤ (less than or equal to) and the upper bound uses < (strictly less than). The value 5.35 would round UP to 5.4, so it's not included.

Percentages Both Papers

Percentage increase/decrease, reverse percentages, compound interest and depreciation.

Percentage Change
Percentage Change Formulas Percentage change = (change / original) x 100

Using multipliers:
Increase by 15%: multiply by 1.15
Decrease by 20%: multiply by 0.80
General: multiply by (1 + r/100) for increase, (1 - r/100) for decrease
Compound Interest and Depreciation
Compound Changes Amount = original x (multiplier)^n
where n = number of time periods

Compound interest: A = P(1 + r/100)^n
Depreciation: A = P(1 - r/100)^n
Reverse Percentages
  • If a price after a 20% increase is 180, the original = 180 / 1.20 = 150
  • If a price after a 15% decrease is 170, the original = 170 / 0.85 = 200
  • Key idea: the amount AFTER the change represents the multiplier, not 100%
Worked Example: Compound Interest
Maria invests 2000 at 3.5% compound interest per year. Find the value after 4 years.
Identify the multiplier: 1 + 3.5/100 = 1.035
Apply the formula: A = 2000 x 1.035^4
Calculate: A = 2000 x 1.14752... = 2295.05
The investment is worth 2295.05 after 4 years
Worked Example: Reverse Percentage
A coat costs 68 in a sale with 15% off. What was the original price?
The sale price represents 85% of the original (100% - 15% = 85%)
So 85% = 68
Original = 68 / 0.85 = 80
The original price was 80

Finding 15% of 68 and adding it back to find the original price: 68 + 10.20 = 78.20. The 15% was taken off the ORIGINAL price, not the sale price. You must divide by the multiplier: 68 / 0.85 = 80.

Quick Check
A car depreciates by 12% each year. It was bought for 18000. What is it worth after 3 years?
Multiplier = 1 - 0.12 = 0.88
Value = 18000 x 0.88^3
= 18000 x 0.681472 = 12266.50 (to nearest penny)
Expressions and Factorising Non-Calculator

Simplifying, expanding brackets and factorising algebraic expressions.

Expanding Brackets
  • Single bracket: 3(2x + 5) = 6x + 15
  • Double brackets (FOIL): (x + 3)(x + 5) = x^2 + 5x + 3x + 15 = x^2 + 8x + 15
  • Squared brackets: (x + 4)^2 = (x + 4)(x + 4) = x^2 + 8x + 16. NOT x^2 + 16!
  • Triple brackets: Expand two first, then multiply by the third
Factorising
Types of Factorising Single bracket: 6x + 15 = 3(2x + 5) [take out HCF]
Double bracket: x^2 + 8x + 15 = (x + 3)(x + 5)
Difference of two squares: x^2 - 49 = (x + 7)(x - 7)
Hard quadratic: 2x^2 + 5x - 3 = (2x - 1)(x + 3)
Worked Example: Factorise 6x^2 + x - 12
Multiply the coefficient of x^2 by the constant: 6 x (-12) = -72
Find two numbers that multiply to -72 and add to +1 (coefficient of x): 9 and -8
Split the middle term: 6x^2 + 9x - 8x - 12
Factorise in pairs: 3x(2x + 3) - 4(2x + 3)
Take out common bracket: (2x + 3)(3x - 4)
(2x + 3)(3x - 4)

(x + 3)^2 = x^2 + 9 (x + 3)^2 = x^2 + 6x + 9. You MUST remember the middle term (2 x x x 3 = 6x). Always expand squared brackets by writing them out as two brackets multiplied.

Quick Check
Factorise: x^2 - 5x - 14
Find two numbers that multiply to -14 and add to -5:
-7 and +2
Answer: (x - 7)(x + 2)
Linear and Simultaneous Equations Both Papers

Solving linear equations and pairs of simultaneous equations.

Linear Equations
  • Do the same operation to both sides to keep the equation balanced
  • Get all the variable terms on one side and constants on the other
  • With fractions: multiply everything by the LCM of denominators first
  • With brackets: expand first, then solve
Simultaneous Equations
Two Methods Elimination: Make coefficients of one variable equal,
then add or subtract equations to eliminate it.

Substitution: Rearrange one equation for one variable,
then substitute into the other equation.
Worked Example: Solve simultaneously 3x + 2y = 16 and 5x - 2y = 24
Notice the y terms are +2y and -2y, so add the equations: 3x + 2y + 5x - 2y = 16 + 24
Simplify: 8x = 40, so x = 5
Substitute x = 5 into equation 1: 3(5) + 2y = 16, so 15 + 2y = 16, so 2y = 1, so y = 0.5
Check in equation 2: 5(5) - 2(0.5) = 25 - 1 = 24. Correct!
x = 5, y = 0.5

Always substitute your answers back into the equation you didn't use to check. If both values satisfy both equations, you know you're right. This takes 10 seconds and can save you marks.

Quadratics Both Papers

Solving quadratic equations by factorising, using the formula and completing the square.

Solving by Factorising
  • Set the equation equal to zero
  • Factorise the quadratic
  • Set each bracket equal to zero and solve
The Quadratic Formula
Quadratic Formula (GIVEN in exam) For ax^2 + bx + c = 0:
x = (-b +/- sqrt(b^2 - 4ac)) / (2a)

The discriminant b^2 - 4ac tells you about roots:
> 0: two distinct real roots
= 0: one repeated root
< 0: no real roots
Completing the Square
Completing the Square x^2 + bx + c = (x + b/2)^2 - (b/2)^2 + c

This gives the turning point: (-(b/2), c - (b/2)^2)
Minimum point for positive x^2, maximum for negative x^2
Worked Example: Solve 2x^2 - 7x + 3 = 0 using the quadratic formula
Identify a = 2, b = -7, c = 3
Calculate discriminant: b^2 - 4ac = (-7)^2 - 4(2)(3) = 49 - 24 = 25
Apply formula: x = (7 +/- sqrt(25)) / (2 x 2) = (7 +/- 5) / 4
Two solutions: x = (7+5)/4 = 3 or x = (7-5)/4 = 0.5
x = 3 or x = 0.5
Worked Example: Complete the square for x^2 + 6x - 4
Halve the coefficient of x: 6 / 2 = 3
Write the squared bracket: (x + 3)^2
Subtract the square of 3: (x + 3)^2 - 9
Add the constant: (x + 3)^2 - 9 - 4 = (x + 3)^2 - 13
(x + 3)^2 - 13. Minimum point is (-3, -13).

Forgetting to set the quadratic equal to zero before factorising: x^2 + 3x = 10, so x(x+3) = 10, so x = 10 or x = 7. First rearrange: x^2 + 3x - 10 = 0, then factorise: (x+5)(x-2) = 0, so x = -5 or x = 2.

Quick Check
Solve x^2 - 3x - 10 = 0 by factorising.
Two numbers that multiply to -10 and add to -3: -5 and +2
(x - 5)(x + 2) = 0
x = 5 or x = -2
Inequalities Both Papers

Solving and representing inequalities on number lines and graphs.

  • Solve like equations, BUT: if you multiply or divide by a negative number, FLIP the inequality sign
  • Open circle (o) for < or > (not included); filled circle for ≤ or ≥ (included)
  • Double inequalities like -3 < 2x + 1 ≤ 7: solve all parts at once
  • Graphical inequalities: draw the line, then shade the correct region
Worked Example: Solve -3 < 2x + 1 ≤ 9 and list integer values
Subtract 1 from all three parts: -3 - 1 < 2x ≤ 9 - 1, so -4 < 2x ≤ 8
Divide all three parts by 2: -2 < x ≤ 4
x is greater than -2 (not including -2) and less than or equal to 4
Integer values: -1, 0, 1, 2, 3, 4

Not flipping the inequality when dividing by a negative: -2x > 6, so x > -3. When you divide both sides by -2, you must flip the sign: -2x > 6 means x < -3.

Sequences Both Papers

Finding and using the nth term of arithmetic, quadratic and geometric sequences.

Linear (Arithmetic) Sequences
nth Term of Linear Sequence Common difference = d (constant difference between terms)
nth term = dn + (first term - d)
OR: nth term = a + (n-1)d where a = first term
Quadratic Sequences
  • The first differences are NOT constant, but the second differences ARE constant
  • If second difference = 2a, then the nth term starts with an^2
  • Subtract an^2 from each term to find the remaining linear part
Geometric Sequences
Geometric Sequence Common ratio r = each term / previous term
nth term = a x r^(n-1) where a = first term
Quick Check
Find the nth term of: 5, 8, 11, 14, 17, ...
Common difference = 3
nth term = 3n + (5 - 3) = 3n + 2
Functions and Straight Line Graphs Both Papers

Straight line equations, gradient, and coordinate geometry.

Straight Line y = mx + c
m = gradient (steepness), c = y-intercept

Gradient = (y2 - y1) / (x2 - x1) [rise / run]
Midpoint = ((x1+x2)/2, (y1+y2)/2)
Distance = sqrt((x2-x1)^2 + (y2-y1)^2)

Parallel lines: same gradient (m1 = m2)
Perpendicular lines: m1 x m2 = -1
Worked Example: Find the equation of the line through (2, 5) perpendicular to y = 3x - 1
Gradient of given line: m = 3
Perpendicular gradient: m = -1/3 (negative reciprocal)
Use y = mx + c with point (2, 5): 5 = (-1/3)(2) + c
Solve for c: 5 = -2/3 + c, so c = 5 + 2/3 = 17/3
y = -x/3 + 17/3 (or equivalently 3y + x = 17)

Thinking perpendicular gradients are just the negative: gradient 3 gives perpendicular gradient -3. Perpendicular gradients are the NEGATIVE RECIPROCAL. Gradient 3 gives perpendicular gradient -1/3. The product must equal -1.

Graph Sketching Both Papers

Recognising and sketching graphs of quadratic, cubic, reciprocal, exponential and trigonometric functions.

  • Quadratic (y = ax^2 + bx + c): U-shape (positive a) or n-shape (negative a). Symmetrical about the turning point.
  • Cubic (y = ax^3 + ...): S-shape going from bottom-left to top-right (positive a) or top-left to bottom-right (negative a).
  • Reciprocal (y = a/x): Two separate curves in opposite quadrants. Never touches the axes (asymptotes).
  • Exponential (y = a^x): Rapid growth curve. Always passes through (0, 1). Never touches x-axis.
  • Trig graphs: sin x and cos x oscillate between -1 and 1 with period 360 degrees. tan x has period 180 degrees with vertical asymptotes.

When sketching graphs, always label the y-intercept (set x = 0), the x-intercepts (set y = 0), and any turning points. These are the key features examiners look for.

Algebraic Fractions Non-Calculator

Simplifying, adding, subtracting and solving equations with algebraic fractions.

  • Simplifying: Factorise numerator and denominator, then cancel common factors
  • Adding/Subtracting: Find a common denominator, just like number fractions
  • Multiplying: Multiply numerators together and denominators together. Simplify first if possible
  • Solving equations: Multiply every term by the common denominator to clear fractions
Worked Example: Simplify (x^2 - 9) / (x^2 + 5x + 6)
Factorise the numerator (difference of two squares): x^2 - 9 = (x+3)(x-3)
Factorise the denominator: x^2 + 5x + 6 = (x+2)(x+3)
Cancel the common factor (x+3): (x+3)(x-3) / (x+2)(x+3) = (x-3)/(x+2)
(x - 3) / (x + 2)

Cancelling individual terms instead of factors: (x^2 + 3x)/(x^2) = 3x/x = 3. You can only cancel FACTORS (things multiplied), not terms (things added). Correct: (x^2 + 3x)/x^2 = x(x+3)/x^2 = (x+3)/x.

Angles Non-Calculator

Angle facts, angles in parallel lines and polygon angle calculations.

Basic Angle Facts
  • Angles on a straight line sum to 180 degrees
  • Angles around a point sum to 360 degrees
  • Vertically opposite angles are equal
  • Angles in a triangle sum to 180 degrees
  • Angles in a quadrilateral sum to 360 degrees
Angles in Parallel Lines
  • Alternate angles (Z-shape): equal
  • Corresponding angles (F-shape): equal
  • Co-interior (allied) angles (C/U-shape): sum to 180 degrees
Polygon Angles
Polygon Angle Formulas Sum of interior angles = (n - 2) x 180 degrees
Each interior angle of regular polygon = (n - 2) x 180 / n
Each exterior angle of regular polygon = 360 / n
Interior + exterior = 180 degrees
Sum of exterior angles always = 360 degrees
Worked Example: Find the interior angle of a regular 9-sided polygon
Sum of interior angles: (9 - 2) x 180 = 7 x 180 = 1260 degrees
Each interior angle: 1260 / 9 = 140 degrees
Each interior angle = 140 degrees
Quick Check
The exterior angle of a regular polygon is 30 degrees. How many sides does it have?
Number of sides = 360 / exterior angle
= 360 / 30 = 12 sides (dodecagon)

When proving angles, always state the angle fact you are using. "Alternate angles are equal" or "angles in a triangle sum to 180 degrees" — examiners need to see the REASON, not just the number.

Area and Perimeter Both Papers

Calculating area and perimeter of 2D shapes including circles, sectors and arcs.

Area Formulas (LEARN these) Rectangle: A = l x w
Triangle: A = 1/2 x b x h
Parallelogram: A = b x h
Trapezium: A = 1/2 x (a + b) x h
Circle: A = pi x r^2
Circumference: C = pi x d = 2 x pi x r

Sector area: A = (theta/360) x pi x r^2
Arc length: L = (theta/360) x 2 x pi x r
Worked Example: Find the area of a sector with radius 8 cm and angle 135 degrees
Use the sector area formula: A = (theta/360) x pi x r^2
Substitute: A = (135/360) x pi x 8^2
Calculate: A = 0.375 x pi x 64 = 24pi = 75.4 cm^2 (1 dp)
Area = 24pi = 75.4 cm^2

Using diameter in circle area formula: A = pi x d^2. The formula uses RADIUS: A = pi x r^2. If given diameter, halve it first! d = 10 means r = 5.

Volume and Surface Area Calculator

3D shapes: prisms, cylinders, cones, spheres and pyramids.

Volume Formulas Prism: V = cross-section area x length
Cylinder: V = pi x r^2 x h
Cone: V = 1/3 x pi x r^2 x h (GIVEN in exam)
Sphere: V = 4/3 x pi x r^3 (GIVEN in exam)
Pyramid: V = 1/3 x base area x height
Surface Area Formulas Cylinder: SA = 2 x pi x r^2 + 2 x pi x r x h
Cone: SA = pi x r x l + pi x r^2 (where l = slant height, GIVEN)
Sphere: SA = 4 x pi x r^2 (GIVEN in exam)
Worked Example: Find the volume of a cone with radius 6 cm and height 10 cm
Use the formula: V = 1/3 x pi x r^2 x h
Substitute: V = 1/3 x pi x 6^2 x 10
Calculate: V = 1/3 x pi x 360 = 120pi = 376.99... cm^3
V = 120pi = 377.0 cm^3 (1 dp)

Leave your answer in terms of pi if the question asks for an exact answer. Otherwise, use pi on your calculator and round appropriately. If no rounding guidance is given, use 3 significant figures.

Transformations Non-Calculator

Reflection, rotation, translation and enlargement including fractional and negative scale factors.

What to include when describing transformations
  • Reflection: State "reflection" + the equation of the mirror line (e.g. y = x, x = -1)
  • Rotation: State "rotation" + angle + direction (clockwise/anticlockwise) + centre of rotation
  • Translation: State "translation" + column vector
  • Enlargement: State "enlargement" + scale factor + centre of enlargement
Scale Factors SF > 1: shape gets bigger
0 < SF < 1: shape gets smaller
SF = -1: same size, inverted through centre
SF < 0: shape inverted and on other side of centre

Describing a transformation incompletely, e.g. "it's been rotated 90 degrees". You MUST include ALL key information: "Rotation, 90 degrees clockwise, centre (0, 0)". Missing any part loses marks.

Congruence and Similarity Both Papers

Proving congruence and using scale factors for similar shapes.

Congruence Conditions
  • SSS: Three sides equal
  • SAS: Two sides and the included angle equal
  • ASA: Two angles and one corresponding side equal
  • RHS: Right angle, hypotenuse and one other side equal
Similarity Scale Factors
Similar Shapes Linear scale factor = k
Area scale factor = k^2
Volume scale factor = k^3

If sides are in ratio 2:5, then:
Areas are in ratio 4:25
Volumes are in ratio 8:125
Quick Check
Two similar cylinders have heights 4 cm and 10 cm. If the smaller has volume 80 cm^3, find the volume of the larger.
Linear scale factor = 10/4 = 2.5
Volume scale factor = 2.5^3 = 15.625
Volume = 80 x 15.625 = 1250 cm^3
Constructions, Loci and Bearings Non-Calculator

Compass and ruler constructions, locus problems, and three-figure bearings.

Key Constructions
  • Perpendicular bisector: The set of points equidistant from two points. Use equal compass arcs from both ends.
  • Angle bisector: The set of points equidistant from two lines. Use compass arcs from the vertex, then arcs from those points.
  • Perpendicular from a point to a line: Arc from the point to cut the line in two places, then perpendicular bisector of those two points.
Bearings
  • Always measured clockwise from North
  • Always given as three figures (e.g. 045 degrees, not 45 degrees)
  • Back bearings differ by 180 degrees

In construction questions, LEAVE YOUR CONSTRUCTION ARCS VISIBLE. The examiner needs to see how you did it. Do not rub them out. Also, bring a sharp pencil and a working compass to the exam.

Pythagoras' Theorem Both Papers

Using Pythagoras' theorem in 2D and 3D.

Pythagoras' Theorem a^2 + b^2 = c^2
where c is the HYPOTENUSE (longest side, opposite right angle)

Finding hypotenuse: c = sqrt(a^2 + b^2)
Finding shorter side: a = sqrt(c^2 - b^2)

3D Pythagoras: diagonal = sqrt(l^2 + w^2 + h^2)
Worked Example: 3D Pythagoras in a cuboid
Find the length of the space diagonal of a cuboid 3 cm by 4 cm by 12 cm.
First find the base diagonal: d = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5
Then use this with the height: D = sqrt(5^2 + 12^2) = sqrt(25 + 144) = sqrt(169) = 13
Space diagonal = 13 cm
Circle Theorems Non-Calculator

The key circle theorems tested at Higher Tier GCSE.

  • Angle at centre is twice the angle at the circumference (from same arc)
  • Angle in a semicircle is 90 degrees (angle subtended by diameter)
  • Angles in the same segment are equal
  • Opposite angles in a cyclic quadrilateral sum to 180 degrees
  • Tangent is perpendicular to the radius at the point of contact
  • Two tangents from an external point are equal in length
  • Alternate segment theorem: angle between tangent and chord equals the angle in the alternate segment

Circle theorem questions almost always require you to STATE THE THEOREM by name. Just writing the angle is not enough. Write: "Angle at centre is twice the angle at the circumference, so x = 2 x 35 = 70 degrees."

Confusing "angle at the centre" and "angle in the same segment" theorems. "Angle at centre" involves one angle at the centre point of the circle and one at the circumference. "Same segment" involves two angles both at the circumference, on the same side of a chord.

Quick Check
In a cyclic quadrilateral, one angle is 72 degrees. What is the opposite angle?
Opposite angles in a cyclic quadrilateral sum to 180 degrees.
Opposite angle = 180 - 72 = 108 degrees
Units and Compound Measures Both Papers

Metric and imperial conversions, and compound measures like speed, density and pressure.

Metric Conversions
  • 1 km = 1000 m; 1 m = 100 cm; 1 cm = 10 mm
  • 1 kg = 1000 g; 1 tonne = 1000 kg
  • 1 litre = 1000 ml = 1000 cm^3
Imperial/Metric Conversions (approximate)
  • 1 inch = 2.5 cm; 1 foot = 30 cm; 1 mile = 1.6 km
  • 1 kg = 2.2 pounds; 1 gallon = 4.5 litres
  • 1 pint = 568 ml (approximately)
Compound Measures
Compound Measure Formulas Speed = distance / time
Density = mass / volume
Pressure = force / area

Remember the formula triangles!
Units matter: check if speed is in km/h or m/s, etc.
Worked Example: Convert 45 km/h to m/s
45 km = 45 x 1000 = 45000 m
1 hour = 60 x 60 = 3600 seconds
Speed = 45000 / 3600 = 12.5 m/s
45 km/h = 12.5 m/s
Trigonometry (SOH CAH TOA) Both Papers

Using trigonometric ratios to find missing sides and angles in right-angled triangles.

SOH CAH TOA sin(angle) = Opposite / Hypotenuse
cos(angle) = Adjacent / Hypotenuse
tan(angle) = Opposite / Adjacent

SOH: sin = O/H
CAH: cos = A/H
TOA: tan = O/A
Steps to Solve
  • Label the sides: Hypotenuse (longest, opposite right angle), Opposite (opposite the angle), Adjacent (next to the angle)
  • Choose the correct ratio based on which two sides you have/need
  • Finding a side: rearrange to isolate it
  • Finding an angle: use inverse trig (sin^-1, cos^-1, tan^-1)
Exact Trig Values (MUST learn)
Anglesincostan
0 degrees010
30 degrees1/2sqrt(3)/21/sqrt(3)
45 degrees1/sqrt(2)1/sqrt(2)1
60 degreessqrt(3)/21/2sqrt(3)
90 degrees10undefined
Worked Example: Find the missing side
A right-angled triangle has hypotenuse 15 cm and an angle of 37 degrees. Find the opposite side.
We have H and need O, so use sin: sin(37) = O / 15
Rearrange: O = 15 x sin(37)
Calculate: O = 15 x 0.6018... = 9.03 cm
Opposite = 9.03 cm (3 sf)

Using SOH CAH TOA on non-right-angled triangles. SOH CAH TOA only works for RIGHT-ANGLED triangles. For other triangles, use the sine rule or cosine rule.

On the non-calculator paper, you need to know the exact trig values. A common question is: "Show that..." using exact values. Make sure you can work with surds and fractions.

Sine and Cosine Rules Calculator

For non-right-angled triangles: sine rule, cosine rule and area formula.

Sine Rule (GIVEN in exam) a / sin A = b / sin B = c / sin C

Use when you have: a side and its opposite angle, plus one other piece
Finding a side: use the formula as written
Finding an angle: flip it: sin A / a = sin B / b
Cosine Rule (GIVEN in exam) a^2 = b^2 + c^2 - 2bc cos A

Use when you have: two sides and the included angle (SAS) or all three sides (SSS)
Finding a side: use as written
Finding an angle: rearrange: cos A = (b^2 + c^2 - a^2) / (2bc)
Area of a Triangle Area = 1/2 x a x b x sin C
(use when you have two sides and the included angle)
Worked Example: Find a side using the cosine rule
Triangle with sides b = 8 cm, c = 11 cm and included angle A = 53 degrees. Find side a.
Apply cosine rule: a^2 = 8^2 + 11^2 - 2(8)(11)cos(53)
Calculate: a^2 = 64 + 121 - 176 x 0.6018... = 185 - 105.93 = 79.07
Square root: a = sqrt(79.07) = 8.89 cm
a = 8.89 cm (3 sf)

How to choose which rule: Do you have a matching pair (side + opposite angle)? Use SINE rule. Do you have SAS or SSS? Use COSINE rule. If you need to find an area with two sides and an included angle, use Area = 1/2 ab sin C.

3D Trigonometry and Pythagoras Calculator

Applying trigonometry and Pythagoras in three-dimensional shapes.

  • Identify the right-angled triangle within the 3D shape
  • Draw it out as a separate 2D triangle
  • Apply Pythagoras or trigonometry as normal
  • You may need to use Pythagoras first to find a side, then trig to find an angle

The key skill is extracting the right triangle from the 3D shape. Draw the 3D shape, identify the triangle you need, then redraw it as a flat 2D triangle with all known measurements.

Vectors Non-Calculator

Column vectors, operations with vectors and geometric proofs.

Vector Basics
  • A vector has magnitude (size) and direction
  • Column vector: top number is horizontal movement, bottom is vertical
  • Negative vector: reverse direction
  • Magnitude: |v| = sqrt(x^2 + y^2)
Vector Operations Addition: add corresponding components
Subtraction: subtract corresponding components
Scalar multiplication: multiply both components

Path: to go from A to B, find a route using known vectors
AB = AO + OB = -OA + OB = OB - OA
Vector Proofs
  • Parallel vectors: one is a scalar multiple of the other (e.g., 2a + 4b = 2(a + 2b) is parallel to a + 2b)
  • Collinear points: vectors between them are parallel AND share a common point
  • Midpoint M of AB: OM = OA + 1/2(AB)
  • Point dividing AB in ratio m:n: OP = OA + m/(m+n) x AB
Quick Check
If OA = 3a + b and OB = a + 5b, find AB.
AB = AO + OB = -OA + OB
= -(3a + b) + (a + 5b)
= -3a - b + a + 5b
= -2a + 4b

Getting the direction wrong: AB = OA - OB. AB = OB - OA (destination minus start). Think of it as: to get from A to B, go back to O first (-OA), then to B (+OB).

Data Collection Both Papers

Sampling methods, questionnaire design and understanding bias.

Sampling Methods
  • Random sampling: Each member has equal chance of being selected (use random number generator)
  • Systematic sampling: Select every kth item from a list (e.g., every 10th person)
  • Stratified sampling: Sample proportionally from each group. Number from group = (group size / total) x sample size
Questionnaire Design
  • Questions should be clear and unambiguous
  • Response boxes should not overlap (e.g. 1-5, 6-10 not 1-5, 5-10)
  • Include a time frame ("in the last week" not "often")
  • Avoid leading or biased questions
  • Include an option for every possible answer

Overlapping response boxes in a questionnaire: "0-10, 10-20, 20-30". Response boxes must not overlap: "0-9, 10-19, 20-29" or "0-10, 11-20, 21-30". Someone who is 10 wouldn't know which box to tick.

Representing Data Both Papers

Different ways to display data: charts, histograms, cumulative frequency and box plots.

Key Chart Types
  • Bar charts: Categorical data, bars don't touch
  • Pie charts: Angle = (frequency / total) x 360
  • Frequency polygons: Plot frequency against midpoint of class, join with straight lines
  • Histograms: Area represents frequency. Frequency density = frequency / class width. Bars touch.
  • Cumulative frequency: Running total, plot against upper boundary, S-shaped curve
  • Box plots: Show minimum, LQ, median, UQ, maximum. Show spread and skew.
  • Stem and leaf: Ordered data with a key. Can be back-to-back for comparisons.
Histograms Frequency density = frequency / class width
frequency = frequency density x class width

The y-axis is FREQUENCY DENSITY, not frequency
The AREA of each bar = the frequency
From Cumulative Frequency
  • Median: read across from n/2 on the y-axis
  • Lower quartile (LQ): read from n/4
  • Upper quartile (UQ): read from 3n/4
  • Interquartile range (IQR) = UQ - LQ

Plotting cumulative frequency against the midpoint of the class. Cumulative frequency is always plotted against the UPPER CLASS BOUNDARY. The total frequency so far applies to everyone up to the end of that class.

Averages and Spread Both Papers

Mean, median and mode from raw data, frequency tables and grouped data.

Averages Mean = sum of values / number of values
Median = middle value when data is ordered
Mode = most common value
Range = highest - lowest

From a frequency table:
Mean = sum(f x x) / sum(f)

From grouped data: use MIDPOINTS for x
This gives an ESTIMATE of the mean
Worked Example: Estimated mean from grouped data
Data: 0-10 (freq 4), 10-20 (freq 7), 20-30 (freq 12), 30-40 (freq 5), 40-50 (freq 2)
Find midpoints: 5, 15, 25, 35, 45
Calculate f x midpoint: 4x5=20, 7x15=105, 12x25=300, 5x35=175, 2x45=90
Sum of fx: 20+105+300+175+90 = 690
Sum of f: 4+7+12+5+2 = 30
Estimated mean: 690/30 = 23
Estimated mean = 23

When comparing two data sets, you need to compare BOTH an average AND a measure of spread. For example: "The mean for group A is higher, showing they tend to score more. The range for group B is smaller, showing their scores are more consistent."

Scatter Graphs and Correlation Both Papers

Drawing and interpreting scatter graphs, correlation and lines of best fit.

  • Positive correlation: As one variable increases, the other increases (points slope upwards)
  • Negative correlation: As one increases, the other decreases (points slope downwards)
  • No correlation: No pattern between variables
  • Line of best fit: Straight line through the data passing through the mean point (x-bar, y-bar)
  • Interpolation: Predicting within the data range (reliable)
  • Extrapolation: Predicting outside the data range (unreliable)

Saying "correlation means causation" — e.g. "more ice cream sales cause more sunburn." Correlation does NOT mean causation. Both could be caused by a third variable (e.g. hot weather). Say "there is a positive correlation between..." not "one causes the other".

Probability Both Papers

Calculating probabilities using sample spaces, tree diagrams, Venn diagrams and conditional probability.

Basic Probability
Probability Rules P(event) = number of favourable outcomes / total outcomes
0 ≤ P(event) ≤ 1
P(not A) = 1 - P(A)
P(A or B) = P(A) + P(B) - P(A and B)
P(A and B) = P(A) x P(B) [if independent]
Expected frequency = probability x number of trials
Tree Diagrams
  • Branches show each possible outcome with its probability
  • Probabilities on branches from same point must sum to 1
  • Multiply along branches (AND)
  • Add between branches (OR)
  • Without replacement: probabilities change on second pick
Venn Diagrams
  • Start by filling in the intersection (overlap) first
  • P(A union B) = P(A) + P(B) - P(A intersection B)
  • Numbers outside both circles represent "neither"
Worked Example: Probability without replacement
A bag has 5 red and 3 blue balls. Two balls are picked without replacement. Find P(both red).
P(1st red) = 5/8
P(2nd red | 1st red) = 4/7 (one less red, one less total)
P(both red) = 5/8 x 4/7 = 20/56 = 5/14
P(both red) = 5/14
Quick Check
The probability of rain on any day is 0.3. Find the probability that it rains on exactly one of two consecutive days.
P(rain then no rain) = 0.3 x 0.7 = 0.21
P(no rain then rain) = 0.7 x 0.3 = 0.21
P(exactly one day) = 0.21 + 0.21 = 0.42

Forgetting to change the probabilities when picking without replacement. P(2nd red) = 5/8 again. Without replacement, the total reduces by 1 and the count of the chosen colour reduces by 1. After picking a red from 5R and 3B, it becomes 4R and 3B, so P(red) = 4/7.

Read carefully whether the question says "with replacement" or "without replacement." If it says someone "eats" a sweet, "doesn't put it back", or "keeps" it, that means without replacement.

Non-Calculator Tips and Techniques Paper 1

Essential mental maths strategies for Paper 1 (Unit T3, 35% of the grade).

Mental Maths Strategies
  • Multiplying by 25: Multiply by 100, divide by 4. E.g., 36 x 25 = 3600 / 4 = 900
  • Multiplying by 99: Multiply by 100, subtract once. E.g., 45 x 99 = 4500 - 45 = 4455
  • Squaring numbers ending in 5: Multiply the tens digit by (tens+1), put 25 on end. 35^2: 3x4=12, answer 1225
  • Percentage of an amount: Find 10% (divide by 10), then build up. 35% = 10% x 3 + 5%
  • Dividing by 0.5: Same as multiplying by 2
  • Long multiplication: Break into parts. 47 x 23 = 47 x 20 + 47 x 3 = 940 + 141 = 1081
Fraction Arithmetic Without Calculator
  • Find common denominators using LCM
  • Convert mixed numbers to improper fractions before multiplying/dividing
  • Always simplify your final answer
  • Remember: dividing by a fraction means flip and multiply

Show ALL your working on the non-calculator paper. Even if you can do it in your head, write down the method. You can get method marks even if your final answer is wrong.

Calculator Tips Paper 2

Getting the most from your calculator on Paper 2 (Unit T6, 65% of the grade).

  • Fraction button (a b/c): Enter fractions directly. Use SHIFT for improper to mixed conversion.
  • ANS button: Uses your previous answer. Great for compound interest: x 1.05 = ANS x 1.05 = ...
  • Brackets: Always use brackets for complex calculations, especially with fractions in formulas
  • SHIFT + ANS: Can recall previous answers in the calculation history
  • Trig mode: Make sure calculator is in DEGREES mode, not radians
  • Square root: The whole expression goes under the root. Use brackets: sqrt(3^2 + 4^2)
  • Negative numbers: Use the (-) button, not the minus key
  • Standard form: Use the x10^x button (or EXP button)

Calculator in radians mode for a trigonometry question (getting wrong answers for sin, cos, tan). ALWAYS check your calculator is in DEG (degrees) mode before the exam. Press SHIFT MODE and select degrees. Look for the D symbol on the display.

Before the exam, practise entering complex expressions correctly. For example, the quadratic formula: enter it all in one go using brackets. Don't round intermediate values — let the calculator keep full accuracy and only round the final answer.

Common Mistakes and Misconceptions Both Papers

The most frequent errors CCEA examiners see — learn to avoid them all.

1. Forgetting to write units. If the question says "cm" then your answer needs "cm" or "cm^2" or "cm^3" as appropriate.

2. Rounding too early. Keep full calculator accuracy throughout and only round at the very end.

3. Not reading the question properly. Underlining key words helps. "Simplify FULLY", "Give exact value", "to 3 significant figures" — miss these and you lose marks.

4. Confusing area and perimeter. Area is the space inside (square units). Perimeter is the distance around the outside (linear units).

5. Using the wrong formula for a shape. Especially mixing up the trapezium formula. Trapezium area = 1/2(a+b)h — both parallel sides added, not multiplied.

6. Sign errors with negative numbers. Remember: negative x negative = positive. -3 x -4 = +12, not -12. And (-3)^2 = 9, but -(3^2) = -9.

7. Not giving both solutions to a quadratic. x^2 = 16 gives x = 4 AND x = -4 (unless context means only positive answers make sense).

8. Mixing up the inequality sign when dividing by negative. If you divide (or multiply) both sides of an inequality by a negative number, you must reverse the inequality sign.

9. Drawing tangents incorrectly. When finding the gradient of a curve at a point, the tangent must just touch the curve at that point. It should not cut through the curve.

10. Not simplifying ratios fully. 6:9 should be simplified to 2:3. Always check if there's a common factor.

11. Probability greater than 1. If your probability comes out greater than 1 or negative, you've made an error. Probability is always between 0 and 1.

12. Using pi = 3.14 instead of the pi button. Always use the pi button on your calculator for full accuracy. 3.14 is not accurate enough.

13. Forgetting to state circle theorem names. You must give the reason, not just the numerical answer.

14. Writing x instead of = in equations. Presentation matters: 2x + 3 = 11 not 2x + 3 x 11.

15. Confusing the mean of grouped data. You must use the midpoint of each class, and this gives an ESTIMATE of the mean (because you don't know exact values).

Command Words Explained Both Papers

Understanding what the examiner wants when they use specific instruction words.

Command WordWhat It Means
CalculateWork out using maths. Show your working and give a numerical answer.
Work outSame as calculate — find the answer using appropriate mathematical methods.
Show thatThe answer is GIVEN. You must demonstrate with clear working HOW to reach it. Every step must be shown.
ProveStart from known facts and use logical steps to reach the conclusion. Must be rigorous.
ExplainGive reasons in words (and maths if helpful). Say WHY, not just what.
JustifyProvide evidence or reasoning to support your answer or conclusion.
EstimateRound numbers to 1 significant figure first, THEN calculate. Show both steps.
SimplifyReduce to simplest form. Collect like terms, cancel fractions, etc.
FactoriseWrite as a product of factors. "Fully" means you can't factorise any further.
Give your answer to...Round to the specified accuracy. Only round the FINAL answer.
HenceUse your answer from the previous part. Don't start from scratch.
Write downNo working needed — just give the answer. (But it's still wise to show thinking.)

"Show that" questions are worth carefully checking — the answer is given, so you know what to aim for. But you MUST show every step. If you skip steps, you'll lose marks even if the answer is correct (since it was given to you).

Mark Scheme Language Both Papers

Understanding how marks are awarded so you can maximise your score.

  • M marks (method): Awarded for showing the correct approach or starting the right method, even if you get the wrong answer
  • A marks (accuracy): Awarded for correct answers. Usually depend on earning the M mark first
  • B marks (independent): Stand-alone marks for a specific correct statement, value or feature
What This Means for You
  • ALWAYS show your working — you can get M marks even with a wrong answer
  • If you make an arithmetic mistake early, you can still get "follow through" marks for correct method after that point
  • Write down formulas before substituting values
  • If a question is worth 4 marks, your answer should have at least 4 distinct steps

A 1-mark question needs just the answer. A 4-mark question needs a full method with clear working. Use the mark allocation as a guide for how much to write.

Time Management Both Papers

Using exam time effectively across both papers.

Paper 1 (Non-Calculator) — 1 hour 15 minutes
  • Worth 35% — around 55 marks
  • Rough guide: 1 minute per mark, plus 20 minutes spare for checking
  • Don't spend too long on any one question — move on and come back
Paper 2 (Calculator) — 2 hours 15 minutes
  • Worth 65% — around 105 marks
  • Rough guide: just over 1 minute per mark
  • Longer paper so pace yourself — don't rush the early questions
  • Use the calculator to CHECK answers where possible
General Tips
  • Read through the whole paper first (2-3 minutes) to identify easy wins
  • Do the questions you're confident about FIRST
  • If stuck for more than 2-3 minutes, move on and come back
  • Leave 10-15 minutes at the end for checking
  • Check you've answered EVERY question — even a guess is better than blank

Grade boundaries for CCEA Higher Tier GCSE Maths are typically around 55-60% for a C*, 70% for a B, and 85%+ for an A*. You don't need to get everything right — focus on collecting all the marks you CAN get.

Grade Boundaries Guidance Both Papers

Typical grade boundaries for CCEA GCSE Higher Tier Mathematics.

GradeTypical % RangeWhat It Means
A*85%+Exceptional — strong on all topics including the hardest questions
A75-84%Excellent — handles most Higher content well
B65-74%Good — confident with core topics, some gaps in harder areas
C*55-64%Solid pass — understands fundamentals well
C45-54%Pass — minimum for most sixth form courses

Note: Grade boundaries vary each year depending on the difficulty of the paper. These are approximate guides based on recent years.

If you're aiming for an A or A*, you need to be confident with the harder topics: algebraic fractions, circle theorems, surds, completing the square, vector proofs, and conditional probability. These are the topics that separate the top grades.

Formulas You MUST Know (Not Given) Learn These

These formulas are NOT provided in the exam. You must memorise them.

Area and Perimeter
2D Shapes Rectangle area: A = l x w
Triangle area: A = 1/2 x b x h
Parallelogram area: A = b x h
Trapezium area: A = 1/2(a + b) x h
Circle area: A = pi x r^2
Circumference: C = pi x d = 2 x pi x r
Volume
3D Shapes Cuboid: V = l x w x h
Prism: V = cross-section area x length
Cylinder: V = pi x r^2 x h
Algebra
Essential Algebra Gradient: m = (y2 - y1)/(x2 - x1)
Midpoint: ((x1+x2)/2, (y1+y2)/2)
Distance: d = sqrt((x2-x1)^2 + (y2-y1)^2)
Straight line: y = mx + c
Pythagoras: a^2 + b^2 = c^2
Trig ratios: sin = O/H, cos = A/H, tan = O/A
Statistics
Statistics Formulas Mean = sum of values / number of values
Probability = favourable outcomes / total outcomes
Relative frequency = frequency / total trials
Other Key Formulas
Percentages and Compound Percentage change = (change / original) x 100
Compound: amount = P x (multiplier)^n
Speed = distance / time
Density = mass / volume
Pressure = force / area
Formulas Given in the Exam Reference

These formulas are provided on the exam formula sheet — but know how to USE them.

Quadratic Formula x = (-b +/- sqrt(b^2 - 4ac)) / (2a)
Trigonometry (Non-right-angled) Sine rule: a/sinA = b/sinB = c/sinC
Cosine rule: a^2 = b^2 + c^2 - 2bc cosA
Area of triangle: A = 1/2 ab sinC
3D Shapes Volume of cone: V = 1/3 pi r^2 h
Curved surface area of cone: A = pi r l
Volume of sphere: V = 4/3 pi r^3
Surface area of sphere: A = 4 pi r^2

Even though these formulas are given, you need to practise USING them correctly. The formula sheet tells you WHAT to use, not HOW to use it. Know which formula applies to which situation.

Key Number Facts Learn These

Essential number facts you should know instantly.

Square Numbers
n123456789101112131415
n^2149162536496481100121144169196225
Cube Numbers
n1234510
n^31827641251000
Prime Numbers to 100
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47,
53, 59, 61, 67, 71, 73, 79, 83, 89, 97
(25 primes in total under 100)
Common Fraction/Decimal/Percentage Equivalents
FractionDecimalPercentage
1/20.550%
1/40.2525%
3/40.7575%
1/30.333...33.3%
2/30.666...66.7%
1/50.220%
1/80.12512.5%
1/100.110%
Quick Check
What are the first 5 cube numbers?
1, 8, 27, 64, 125
Angle Facts Reference Reference
Angle Facts Summary Straight line: 180 degrees
Full turn: 360 degrees
Right angle: 90 degrees
Triangle: 180 degrees
Quadrilateral: 360 degrees
Polygon interior sum: (n-2) x 180
Regular polygon interior angle: (n-2) x 180 / n
Regular polygon exterior angle: 360 / n
Interior + exterior = 180 degrees

Parallel lines:
Alternate (Z) angles are equal
Corresponding (F) angles are equal
Co-interior (C/U) angles sum to 180
Unit Conversion Reference Reference
Length
1 km = 1000 m
1 m = 100 cm
1 cm = 10 mm
1 mile = 1.6 km (approx)
1 inch = 2.54 cm
Mass
1 kg = 1000 g
1 tonne = 1000 kg
1 kg = 2.2 pounds (approx)
Volume / Capacity
1 litre = 1000 ml
1 litre = 1000 cm^3
1 m^3 = 1 000 000 cm^3
1 gallon = 4.5 litres (approx)
Area and Volume Scale
1 m^2 = 10 000 cm^2 (100^2)
1 km^2 = 1 000 000 m^2 (1000^2)
1 m^3 = 1 000 000 cm^3 (100^3)
Time
1 hour = 60 minutes = 3600 seconds
1 day = 24 hours

Converting minutes to hours: divide by 60
45 mins = 45/60 = 0.75 hours (NOT 0.45!)

Converting 2 hours 30 minutes to 2.30 hours. 30 minutes = 30/60 = 0.5 hours, so 2 hours 30 minutes = 2.5 hours. Time does NOT work in decimals of 100!

Trigonometric Exact Values Must Know

You must know these exact values for the non-calculator paper.

Anglesincostan
0 degrees010
30 degrees1/2sqrt(3)/21/sqrt(3) = sqrt(3)/3
45 degrees1/sqrt(2) = sqrt(2)/21/sqrt(2) = sqrt(2)/21
60 degreessqrt(3)/21/2sqrt(3)
90 degrees10undefined

Notice the symmetry: sin and cos values are "swapped" for 30 and 60 degrees. Also, sin values go 0, 1/2, sqrt(2)/2, sqrt(3)/2, 1 — the numerators are sqrt(0), sqrt(1), sqrt(2), sqrt(3), sqrt(4) all over 2. This pattern can help you remember.

Quick Check
What is the exact value of sin(60) x cos(30)?
sin(60) = sqrt(3)/2
cos(30) = sqrt(3)/2
sin(60) x cos(30) = sqrt(3)/2 x sqrt(3)/2 = 3/4
Home Study GCSE Maths Science English