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GCSE Chemistry

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Atoms: The Building Blocks

All matter is made of atoms. An atom is the smallest part of an element that can take part in chemical reactions.

Sub-atomic Particles

ParticleRelative MassRelative ChargeLocation
Proton1+1Nucleus
Neutron10Nucleus
Electron1/1836 (negligible)-1Shells (orbits)

Atomic Number and Mass Number

  • Atomic number (Z) = number of protons = number of electrons (in a neutral atom)
  • Mass number (A) = protons + neutrons
  • Number of neutrons = mass number - atomic number
Number of neutrons = A - Z

Isotopes

Isotopes are atoms of the same element with the same number of protons but different numbers of neutrons. They have identical chemical properties but different physical properties (e.g. density, rate of diffusion).

Example: Carbon-12 (6p, 6n) and Carbon-14 (6p, 8n) are isotopes of carbon.

Exam Tip
Isotopes have the same atomic number but different mass numbers. They react chemically in the same way because they have the same electron configuration.
Quick Check

Chlorine has two isotopes: Cl-35 and Cl-37. Both have 17 protons. How many neutrons does each have?

Cl-35: 35 - 17 = 18 neutrons
Cl-37: 37 - 17 = 20 neutrons
Electronic Configuration

Electrons are arranged in shells (energy levels) around the nucleus.

Rules for Filling Shells

  • 1st shell holds up to 2 electrons
  • 2nd shell holds up to 8 electrons
  • 3rd shell holds up to 8 electrons (at GCSE level)
  • Electrons fill the lowest energy shell first

Examples

ElementAtomic NumberConfiguration
Hydrogen11
Carbon62, 4
Oxygen82, 6
Sodium112, 8, 1
Chlorine172, 8, 7
Calcium202, 8, 8, 2

Noble Gas Stability

Atoms are most stable when they have a full outer shell of electrons (like the noble gases: He = 2, Ne = 2,8, Ar = 2,8,8). Atoms bond to achieve this stable configuration.

Exam Tip
The number of electrons in the outer shell determines the group number for main group elements. E.g. sodium (2,8,1) is in Group 1.
The Periodic Table

Elements are arranged in order of increasing atomic number. The periodic table is arranged in groups (columns) and periods (rows).

Groups

  • Group number = number of electrons in outer shell
  • Elements in the same group have similar chemical properties
  • Group 1: Alkali metals (Li, Na, K) — very reactive, form +1 ions
  • Group 7: Halogens (F, Cl, Br, I) — reactive non-metals, form -1 ions
  • Group 0: Noble gases (He, Ne, Ar) — unreactive, full outer shells

Periods

  • Period number = number of occupied electron shells
  • Properties change gradually across a period (metallic to non-metallic)

Metals and Non-metals

  • Metals: left side and centre — lose electrons, form positive ions, good conductors
  • Non-metals: right side — gain or share electrons, form negative ions or covalent bonds, poor conductors (except graphite)

Group 1 Trends

Going down Group 1: reactivity increases, melting point decreases, density increases. The outer electron is further from the nucleus and easier to lose.

Group 7 Trends

Going down Group 7: reactivity decreases, melting/boiling points increase. The outer shell is further from the nucleus, making it harder to attract an extra electron.

Common Mistake
Mixing up trends: Group 1 metals get MORE reactive going down, but Group 7 non-metals get LESS reactive going down. The reasons are different!
Quick Check

Potassium is below sodium in Group 1. Which is more reactive and why?

Potassium is more reactive. Its outer electron is further from the nucleus (more shells), so there is less nuclear attraction, making it easier to lose.
Ionic Bonding

Ionic bonding occurs between metals and non-metals. Metal atoms lose electrons to form positive ions (cations), and non-metal atoms gain electrons to form negative ions (anions).

Example: Sodium Chloride (NaCl)

  • Sodium (2,8,1) loses 1 electron → Na+ (2,8)
  • Chlorine (2,8,7) gains 1 electron → Cl (2,8,8)
  • The oppositely charged ions attract each other with strong electrostatic forces
Na → Na+ + e
Cl + e → Cl

Dot-and-Cross Diagrams

Show the transfer of electrons using dots for one atom and crosses for the other. Only outer shell electrons need to be shown at GCSE. Put square brackets around ions and show the charge.

Properties of Ionic Compounds

  • High melting and boiling points — strong electrostatic forces between ions require lots of energy to overcome
  • Conduct electricity when molten or dissolved — ions are free to move and carry charge
  • Do not conduct when solid — ions are held in a fixed lattice
  • Usually soluble in water
  • Form giant ionic lattices (regular 3D structures)
Exam Tip
In dot-and-cross diagrams, always show the charge on each ion and use square brackets. Remember: only show the outer shell electrons.
Common Mistake
Saying ionic compounds "contain molecules" — they do NOT. They form a giant lattice of ions, not discrete molecules.
Covalent Bonding

Covalent bonding occurs between non-metal atoms. Atoms share pairs of electrons to achieve a full outer shell.

Simple Molecular Substances

MoleculeFormulaShared PairsBond Type
HydrogenH₂1Single bond
WaterH₂O2Two single bonds
OxygenO₂2Double bond (O=O)
NitrogenN₂3Triple bond
MethaneCH₄4Four single bonds
Carbon dioxideCO₂4Two double bonds (O=C=O)

Properties of Simple Molecular Substances

  • Low melting and boiling points — weak intermolecular forces (not the covalent bonds) are easily overcome
  • Do not conduct electricity — no free electrons or ions
  • Often gases or liquids at room temperature

Giant Covalent Structures

Diamond: each carbon bonded to 4 others in a tetrahedral arrangement. Very hard, very high melting point, does not conduct electricity (no free electrons).

Graphite: each carbon bonded to 3 others in flat layers. Layers slide over each other (soft, used as lubricant). One delocalised electron per carbon — conducts electricity. High melting point.

Graphene: a single layer of graphite. Excellent conductor of electricity and heat. Very strong for its mass.

Common Mistake
Saying "covalent bonds are weak" when explaining low boiling points of simple molecules. The covalent bonds are strong! It is the intermolecular forces between molecules that are weak.
Quick Check

Why does diamond not conduct electricity but graphite does?

In diamond, all four outer electrons of each carbon are used in covalent bonds — no free electrons to carry charge.
In graphite, each carbon uses only 3 of its 4 outer electrons for bonding. The 4th electron is delocalised and free to move, allowing graphite to conduct electricity.
Metallic Bonding

In metals, the outer electrons are delocalised (free to move). This creates a structure of positive metal ions surrounded by a "sea of electrons".

Metallic Bond

The strong electrostatic attraction between the positive metal ions and the delocalised electrons is the metallic bond.

Properties of Metals

  • Good conductors of electricity — delocalised electrons can flow as current
  • Good conductors of heat — delocalised electrons transfer kinetic energy
  • Malleable and ductile — layers of ions can slide over each other without breaking the metallic bond
  • High melting points (generally) — strong metallic bonds need lots of energy to break
  • Shiny (lustrous) — delocalised electrons reflect light
Exam Tip
Always refer to the "sea of delocalised electrons" and the "electrostatic attraction between positive ions and delocalised electrons" when describing metallic bonding. These key phrases score marks.
Types of Reaction

Key Reaction Types

  • Combustion: substance reacts with oxygen, releasing heat and light. E.g. CH₄ + 2O₂ → CO₂ + 2H₂O
  • Thermal decomposition: a substance breaks down when heated. E.g. CaCO₃ → CaO + CO₂
  • Neutralisation: acid + base → salt + water. E.g. HCl + NaOH → NaCl + H₂O
  • Displacement: a more reactive element replaces a less reactive one. E.g. Zn + CuSO₄ → ZnSO₄ + Cu
  • Oxidation: gain of oxygen or loss of electrons (OIL — Oxidation Is Loss)
  • Reduction: loss of oxygen or gain of electrons (RIG — Reduction Is Gain)
  • Precipitation: two solutions react to form an insoluble solid (precipitate). E.g. AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
OIL RIG: Oxidation Is Loss, Reduction Is Gain (of electrons)
Exam Tip
In displacement reactions, always check the reactivity series. A more reactive metal will displace a less reactive metal from its compound.
Word & Symbol Equations (Balancing)

Chemical equations must be balanced — the same number of each type of atom on both sides (conservation of mass).

Steps to Balance an Equation

  1. Write the unbalanced equation with correct formulae
  2. Count atoms of each element on both sides
  3. Adjust coefficients (big numbers in front) to balance — never change the formulae
  4. Check all atoms balance

Example

Unbalanced: Mg + O₂ → MgO
Balanced: 2Mg + O₂ → 2MgO

State Symbols

SymbolState
(s)Solid
(l)Liquid
(g)Gas
(aq)Aqueous (dissolved in water)
Common Mistake
Changing the small (subscript) numbers in formulae to balance an equation. You must only change the big numbers (coefficients) in front of formulae. Changing subscripts changes the substance!
Acids and Bases

The pH Scale

  • pH 0-6: Acidic (lower = stronger acid)
  • pH 7: Neutral
  • pH 8-14: Alkaline (higher = stronger alkali)

Indicators: Litmus (red in acid, blue in alkali), Universal indicator (range of colours), Phenolphthalein (colourless in acid, pink in alkali).

Strong vs Weak Acids

  • Strong acids (HCl, H₂SO₄, HNO₃) are fully dissociated (ionised) in water
  • Weak acids (CH₃COOH, H₂CO₃) are only partially dissociated — equilibrium lies to the left

Reactions of Acids

acid + metal → salt + hydrogen
acid + metal oxide → salt + water
acid + metal hydroxide → salt + water
acid + metal carbonate → salt + water + carbon dioxide

Examples

  • HCl + NaOH → NaCl + H₂O
  • 2HCl + Mg → MgCl₂ + H₂
  • H₂SO₄ + CuO → CuSO₄ + H₂O
  • 2HCl + CaCO₃ → CaCl₂ + H₂O + CO₂

Naming Salts

  • Hydrochloric acid (HCl) makes chlorides
  • Sulfuric acid (H₂SO₄) makes sulfates
  • Nitric acid (HNO₃) makes nitrates
Exam Tip
The salt name = metal name + acid ending. E.g. magnesium + hydrochloric acid = magnesium chloride.
Quick Check

What salt is formed when zinc reacts with sulfuric acid? Write the word equation.

zinc + sulfuric acid → zinc sulfate + hydrogen
Zn + H₂SO₄ → ZnSO₄ + H₂
Salts and Electrolysis

Making Salts

  • Soluble salts: react acid with excess insoluble base/carbonate, filter off excess, evaporate
  • Titration method: for soluble base + acid — use indicator to find exact volumes

Electrolysis

Electrolysis is the decomposition of a compound using electricity. The compound must be molten or dissolved so ions are free to move.

  • Anode = positive electrode — negative ions (anions) are attracted here and oxidised
  • Cathode = negative electrode — positive ions (cations) are attracted here and reduced
PANIC: Positive = Anode, Negative Is Cathode

Electrolysis of Molten Compounds

E.g. Molten lead bromide (PbBr₂):

  • Cathode: Pb2+ + 2e → Pb (lead metal formed)
  • Anode: 2Br → Br₂ + 2e (bromine gas formed)

Electrolysis of Solutions

Water provides H+ and OH ions. At GCSE level:

  • At the cathode: if the metal is more reactive than hydrogen, hydrogen gas is produced. If less reactive, the metal is deposited.
  • At the anode: if a halide ion is present, the halogen is produced. Otherwise, oxygen is produced.

Electroplating

Coating an object with a thin layer of metal using electrolysis. The object to be plated is the cathode. The plating metal is the anode. The electrolyte contains ions of the plating metal.

Required Practical
Electrolysis of copper sulfate solution with copper electrodes. Copper is deposited at the cathode and dissolves from the anode. The solution stays blue. This demonstrates purification of copper.
Electrolysis: In-Depth

Electrolysis of Molten Compounds

When an ionic compound is melted, the ions are free to move. Only two ions are present, so the products are straightforward:

Molten CompoundAt Cathode (-)At Anode (+)
Lead bromide (PbBr₂)Lead (Pb) metalBromine (Br₂) gas
Sodium chloride (NaCl)Sodium (Na) metalChlorine (Cl₂) gas
Aluminium oxide (Al₂O₃)Aluminium (Al) metalOxygen (O₂) gas
Zinc chloride (ZnCl₂)Zinc (Zn) metalChlorine (Cl₂) gas

Electrolysis of Aqueous Solutions

In aqueous solutions, water (H₂O) also provides ions: H+ and OH. This means there is competition at each electrode.

Rules for Products at Electrodes

ElectrodeRuleDetail
Cathode (-)If the metal is more reactive than hydrogenHydrogen gas is produced (H+ ions are discharged)
Cathode (-)If the metal is less reactive than hydrogenMetal is deposited (metal ions are discharged)
Anode (+)If a halide ion (Cl, Br, I) is presentThe halogen is produced
Anode (+)If no halide is present (e.g. sulfate, nitrate)Oxygen gas is produced (OH ions are discharged)

Half Equations at Electrodes

At the cathode (reduction — gain of electrons):

Cu2+ + 2e → Cu (copper deposited)
2H+ + 2e → H₂ (hydrogen gas produced)

At the anode (oxidation — loss of electrons):

2Cl → Cl₂ + 2e (chlorine gas produced)
4OH → 2H₂O + O₂ + 4e (oxygen gas produced)

Examples of Aqueous Electrolysis

SolutionCathode ProductAnode ProductReason
Copper sulfate (CuSO₄)Copper (Cu)Oxygen (O₂)Cu less reactive than H; no halide present
Sodium chloride (NaCl)Hydrogen (H₂)Chlorine (Cl₂)Na more reactive than H; halide (Cl) present
Sodium sulfate (Na₂SO₄)Hydrogen (H₂)Oxygen (O₂)Na more reactive than H; no halide present
Copper chloride (CuCl₂)Copper (Cu)Chlorine (Cl₂)Cu less reactive than H; halide (Cl) present

Extraction of Aluminium

Aluminium is too reactive to be extracted by reduction with carbon. Instead, it is extracted by electrolysis of molten aluminium oxide (Al₂O₃) dissolved in cryolite (Na₃AlF₆).

  • Cryolite lowers the melting point of aluminium oxide from ~2050 °C to ~950 °C, saving energy and cost
  • Cathode (carbon): Al3+ + 3e → Al (molten aluminium sinks to the bottom and is tapped off)
  • Anode (carbon): 2O2− → O₂ + 4e (oxygen gas produced)
  • The carbon anodes burn away (react with oxygen at high temperature: C + O₂ → CO₂) and must be regularly replaced
  • The process is expensive due to the high energy requirement (large electric current needed)
Overall: 2Al₂O₃ → 4Al + 3O₂

Electroplating

Electroplating is coating an object with a thin layer of metal using electrolysis.

  • Cathode: the object to be plated
  • Anode: the plating metal (it dissolves to replace metal ions in solution)
  • Electrolyte: a solution containing ions of the plating metal

Reasons for electroplating: appearance (silver/gold plating for jewellery), corrosion resistance (chromium plating on steel), hardness (chromium plating on tools).

Industrial Uses of Electrolysis

ProcessUse
Extraction of aluminiumProduction of aluminium metal for construction, packaging, transport
Purification of copperPure copper for electrical wiring (impure copper anode, pure copper cathode, CuSO₄ electrolyte)
Electrolysis of brine (NaCl solution)Produces chlorine (disinfectants, PVC), hydrogen (fuel, making margarine), sodium hydroxide (soap, paper, bleach)
ElectroplatingCoating objects with metals for appearance or protection
Exam Tip
When writing half equations, always check that the charges balance AND that the number of atoms balance on both sides. Remember: cathode = reduction (gain electrons), anode = oxidation (lose electrons).
Quick Check

What products would be formed at each electrode during the electrolysis of potassium iodide (KI) solution?

Cathode: Hydrogen gas (H₂) — potassium is more reactive than hydrogen, so H+ ions are discharged.
Anode: Iodine (I₂) — iodide is a halide ion, so the halogen is produced.
Half equations: 2H+ + 2e → H₂ (cathode); 2I → I₂ + 2e (anode)
Rates of Reaction

Collision Theory

For a reaction to occur, particles must collide with sufficient energy. The minimum energy needed is the activation energy. The rate of reaction depends on the frequency of successful collisions.

Factors Affecting Rate

FactorEffectExplanation
Increase concentrationIncreases rateMore particles per unit volume = more frequent collisions
Increase temperatureIncreases rateParticles move faster = more frequent collisions AND more particles exceed activation energy
Increase surface area (smaller pieces)Increases rateMore exposed particles available for collision
Add a catalystIncreases rateProvides alternative pathway with lower activation energy

Catalyst: a substance that speeds up a reaction without being used up. It is not consumed and can be recovered unchanged.

Required Practical
Rates of reaction: Investigate the effect of concentration on the rate of reaction between sodium thiosulfate and hydrochloric acid (disappearing cross experiment). Or: magnesium ribbon with different concentrations of HCl, measuring gas volume over time.
Common Mistake
Saying temperature increases the "number of collisions" only. You MUST also say that more particles have energy greater than or equal to the activation energy. Both points are needed for full marks.
Quick Check

A student uses large marble chips with HCl. Suggest two changes to increase the rate.

1. Use smaller marble chips (powder) to increase surface area
2. Use a higher concentration of HCl
(Also valid: increase temperature, or add a catalyst)
Exothermic and Endothermic Reactions

Exothermic Reactions

  • Transfer energy to the surroundings (temperature increases)
  • Examples: combustion, neutralisation, oxidation, hand warmers
  • Energy released when bonds are formed is greater than energy needed to break bonds

Endothermic Reactions

  • Take in energy from the surroundings (temperature decreases)
  • Examples: thermal decomposition, photosynthesis, cold packs (ammonium nitrate dissolving)
  • Energy needed to break bonds is greater than energy released when bonds are formed

Energy Profiles

Exothermic: products are at a lower energy level than reactants. Energy change is negative.

Endothermic: products are at a higher energy level than reactants. Energy change is positive.

Both profiles show an activation energy hump that must be overcome for the reaction to proceed.

Bond Energies

Breaking bonds = endothermic (energy IN). Making bonds = exothermic (energy OUT).

Energy change = energy to break bonds - energy released making bonds

If the answer is negative → exothermic. If positive → endothermic.

Worked Example

Calculate the energy change for: H₂ + Cl₂ → 2HCl

Bond energies: H-H = 436 kJ/mol, Cl-Cl = 242 kJ/mol, H-Cl = 431 kJ/mol

Step 1: Energy to break bonds = 436 + 242 = 678 kJ
Step 2: Energy released making bonds = 2 × 431 = 862 kJ
Step 3: Energy change = 678 - 862 = -184 kJ/mol
Answer: -184 kJ/mol (exothermic — negative value)
Exam Tip
A catalyst lowers the activation energy but does NOT change the overall energy change of the reaction. On an energy profile, the hump is smaller but the start and end energy levels stay the same.
Chemical Equilibrium

Reversible Reactions

A reversible reaction is one that can go in both directions — products can react to re-form the original reactants. The symbol ⇌ is used instead of →.

A + B ⇌ C + D

Example: Heating hydrated copper sulfate:

CuSO₄·5H₂O ⇌ CuSO₄ + 5H₂O
(blue)       (white)

The forward reaction is endothermic (heating drives off water). The reverse reaction is exothermic (adding water releases heat). In any reversible reaction, if the forward reaction is exothermic, the reverse is endothermic by the same amount, and vice versa.

Dynamic Equilibrium

When a reversible reaction occurs in a closed system (nothing can enter or leave), it reaches dynamic equilibrium:

  • The rate of the forward reaction equals the rate of the reverse reaction
  • The concentrations of reactants and products remain constant (but not necessarily equal)
  • Both reactions are still occurring — it is dynamic, not static

Le Chatelier's Principle

Le Chatelier's principle: if a system at equilibrium is subjected to a change, the equilibrium will shift to oppose that change.

ChangeEffect on EquilibriumExplanation
Increase concentration of reactantShifts right (towards products)System opposes the increase by using up the added reactant
Decrease concentration of productShifts right (towards products)System opposes the decrease by making more product
Increase temperatureShifts in the endothermic directionSystem opposes the extra heat by absorbing it
Decrease temperatureShifts in the exothermic directionSystem opposes the cooling by releasing heat
Increase pressureShifts towards the side with fewer gas molesSystem opposes the pressure increase by reducing the number of gas molecules
Decrease pressureShifts towards the side with more gas molesSystem opposes the pressure decrease by producing more gas molecules
Add a catalystNo shift — equilibrium reached fasterCatalyst speeds up both forward and reverse reactions equally

The Haber Process

The industrial manufacture of ammonia:

N₂(g) + 3H₂(g) ⇌ 2NH₃(g) ΔH = -92 kJ/mol (exothermic)

Conditions chosen as a compromise:

ConditionValue UsedReason
Temperature450 °CLow temperature favours forward (exothermic) reaction, but too low = very slow rate. 450 °C is a compromise between yield and rate.
Pressure200 atmHigh pressure favours forward reaction (4 moles gas → 2 moles gas). Very high pressure is expensive and dangerous.
CatalystIron catalystSpeeds up the reaction so equilibrium is reached faster. Does not change the yield.

Unreacted nitrogen and hydrogen are recycled back through the reactor to improve overall yield.

The Contact Process

The industrial manufacture of sulfuric acid (H₂SO₄). The key equilibrium step is:

2SO₂(g) + O₂(g) ⇌ 2SO₃(g) ΔH = -196 kJ/mol (exothermic)

Conditions: temperature of 450 °C, 1-2 atm pressure, vanadium(V) oxide (V₂O₅) catalyst. The SO₃ produced is then dissolved in concentrated H₂SO₄ and diluted with water to form more sulfuric acid.

Exam Tip
A catalyst does NOT change the position of equilibrium or the yield. It only makes equilibrium reached faster. This is a very common exam question.
Common Mistake
Saying "the reaction stops at equilibrium" — both forward and reverse reactions are still occurring at equal rates. It is a dynamic equilibrium.
Quick Check

In the Haber process, what would happen to the yield of ammonia if the pressure was increased?

The yield of ammonia would increase.
There are 4 moles of gas on the left (1 N₂ + 3 H₂) and 2 moles on the right (2 NH₃).
Increasing pressure shifts equilibrium to the side with fewer gas moles (right), producing more ammonia.
Redox Reactions

Definitions of Oxidation and Reduction

Oxidation and reduction always happen together — these are called redox reactions.

TermIn terms of oxygenIn terms of electrons
OxidationGain of oxygenLoss of electrons
ReductionLoss of oxygenGain of electrons
OIL RIG: Oxidation Is Loss, Reduction Is Gain (of electrons)

Oxidation States (Oxidation Numbers)

Oxidation states are a way of tracking electron transfer. Rules:

  • Elements in their natural state have an oxidation state of 0 (e.g. O₂, Fe, Na)
  • Simple ions have an oxidation state equal to their charge (e.g. Na+ = +1, Cl = -1)
  • Oxygen is usually -2 in compounds
  • Hydrogen is usually +1 in compounds
  • The sum of oxidation states in a compound = 0
  • The sum in a polyatomic ion = the charge on the ion

If an element's oxidation state increases, it has been oxidised. If it decreases, it has been reduced.

Identifying Redox Reactions

Example: Mg + CuO → MgO + Cu

  • Magnesium goes from 0 to +2 (oxidation state increases) — it is oxidised (loses electrons)
  • Copper goes from +2 to 0 (oxidation state decreases) — it is reduced (gains electrons)
  • Magnesium gains oxygen — oxidised. Copper loses oxygen — reduced.

Displacement Reactions as Redox

All displacement reactions are redox reactions:

Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s)
  • Zinc is oxidised: Zn → Zn2+ + 2e (loses electrons, oxidation state 0 → +2)
  • Copper is reduced: Cu2+ + 2e → Cu (gains electrons, oxidation state +2 → 0)

A more reactive metal will displace a less reactive metal from a solution of its salt. This is because the more reactive metal is a better electron donor (more easily oxidised).

Reactivity Series and Redox

MetalReactivityEase of Oxidation
Potassium (K)Most reactiveMost easily oxidised (loses electrons most readily)
Sodium (Na)
Calcium (Ca)||
Magnesium (Mg)||
Aluminium (Al)||
Zinc (Zn)||
Iron (Fe)||
Hydrogen (H)||
Copper (Cu)||
Silver (Ag)
Gold (Au)Least reactiveLeast easily oxidised

Rusting as a Redox Process

Rusting is the corrosion of iron. It requires both oxygen and water.

4Fe(s) + 3O₂(g) + 6H₂O(l) → 4Fe(OH)₃(s)
Iron(III) hydroxide → hydrated iron(III) oxide (rust)
  • Iron is oxidised: Fe → Fe3+ + 3e
  • Oxygen is reduced: O₂ + 2H₂O + 4e → 4OH

Prevention of Rusting

MethodHow It Works
Painting / oiling / greasingBarrier method — prevents oxygen and water reaching the iron
Plastic coatingBarrier method — physical layer prevents contact with air and water
Galvanising (zinc coating)Barrier method AND sacrificial protection — zinc is more reactive and is oxidised instead of iron
Sacrificial protectionA more reactive metal (e.g. zinc or magnesium) is attached to the iron. The more reactive metal is preferentially oxidised.
Stainless steel (alloying with chromium)Chromium forms a protective oxide layer on the surface
Exam Tip
In displacement reactions, always identify what is oxidised and what is reduced. State the electron transfer AND the change in oxidation state for full marks.
Quick Check

In the reaction Fe₂O₃ + 3CO → 2Fe + 3CO₂, identify what is oxidised and what is reduced.

Carbon monoxide (CO) is oxidised — it gains oxygen to form CO₂. Carbon goes from +2 to +4.
Iron(III) oxide (Fe₂O₃) is reduced — it loses oxygen to form Fe. Iron goes from +3 to 0.
CO is the reducing agent (it reduces the iron oxide). Fe₂O₃ is the oxidising agent.
Gas Laws

Kinetic Theory of Gases

In a gas, particles are in constant random motion. They collide with each other and with the walls of the container. The pressure of a gas is caused by particles colliding with the container walls.

  • Increasing temperature makes particles move faster → more frequent and harder collisions → pressure increases
  • Decreasing volume means particles are closer together → more frequent collisions → pressure increases
  • Increasing the number of particles increases the frequency of collisions → pressure increases

Boyle's Law (constant temperature)

At constant temperature, the pressure of a gas is inversely proportional to its volume.

P₁V₁ = P₂V₂

pressure × volume = constant (at fixed temperature)

If you double the pressure, the volume halves (and vice versa).

Worked Example

A gas has a volume of 500 cm³ at a pressure of 100 kPa. What is the volume at 200 kPa? (Temperature constant)

Step 1: P₁V₁ = P₂V₂
Step 2: 100 × 500 = 200 × V₂
Step 3: 50 000 = 200 × V₂
Step 4: V₂ = 50 000 ÷ 200 = 250 cm³
Answer: 250 cm³ (volume halved as pressure doubled)

Charles's Law (constant pressure)

At constant pressure, the volume of a gas is directly proportional to its absolute temperature (in Kelvin).

V₁ / T₁ = V₂ / T₂

Temperature must be in Kelvin: K = °C + 273

If you double the temperature (in Kelvin), the volume doubles.

Pressure Law (constant volume)

At constant volume, the pressure of a gas is directly proportional to its absolute temperature (in Kelvin).

P₁ / T₁ = P₂ / T₂

Temperature must be in Kelvin: K = °C + 273

Combined Gas Law

When temperature, pressure, and volume all change:

P₁V₁ / T₁ = P₂V₂ / T₂
Worked Example

A gas occupies 600 cm³ at 27 °C and 100 kPa. What volume does it occupy at 127 °C and 200 kPa?

Step 1: Convert to Kelvin: T₁ = 27 + 273 = 300 K, T₂ = 127 + 273 = 400 K
Step 2: P₁V₁ / T₁ = P₂V₂ / T₂
Step 3: (100 × 600) / 300 = (200 × V₂) / 400
Step 4: 200 = 200 × V₂ / 400
Step 5: V₂ = (200 × 400) / 200 = 400 cm³
Answer: 400 cm³

Summary of Gas Laws

LawRelationshipKept ConstantEquation
Boyle's LawP ∝ 1/VTemperatureP₁V₁ = P₂V₂
Charles's LawV ∝ TPressureV₁/T₁ = V₂/T₂
Pressure LawP ∝ TVolumeP₁/T₁ = P₂/T₂
CombinedPV/T = constantNothingP₁V₁/T₁ = P₂V₂/T₂
Common Mistake
Forgetting to convert temperature to Kelvin when using Charles's Law or the Pressure Law. You MUST use Kelvin (add 273 to °C). Using °C will give the wrong answer.
Exam Tip
Check your answer makes sense: if pressure increases at constant temperature, volume should decrease. If temperature increases at constant pressure, volume should increase.
Relative Atomic Mass & Relative Formula Mass

Relative atomic mass (Ar) is the average mass of an atom of an element compared to 1/12 of a carbon-12 atom. Found on the periodic table.

Relative formula mass (Mr) is the sum of all the Ar values in a formula.

Worked Example 1

Calculate the Mr of calcium carbonate, CaCO₃. (Ca = 40, C = 12, O = 16)

Step 1: Ca = 40
Step 2: C = 12
Step 3: O₃ = 3 × 16 = 48
Step 4: Mr = 40 + 12 + 48 = 100
Mr of CaCO₃ = 100
Worked Example 2

Calculate the Mr of magnesium hydroxide, Mg(OH)₂. (Mg = 24, O = 16, H = 1)

Step 1: Mg = 24
Step 2: (OH)₂ means 2 × O and 2 × H = 2(16) + 2(1) = 34
Step 3: Mr = 24 + 34 = 58
Mr of Mg(OH)₂ = 58
Moles

A mole is the amount of substance that contains 6.02 × 10²³ particles (Avogadro's number).

moles = mass (g) ÷ Mr
mass = moles × Mr
Mr = mass ÷ moles
Worked Example 3

How many moles are in 11 g of carbon dioxide, CO₂? (C = 12, O = 16)

Step 1: Calculate Mr of CO₂ = 12 + 2(16) = 44
Step 2: moles = mass ÷ Mr = 11 ÷ 44 = 0.25 mol
Answer: 0.25 mol
Worked Example 4

What is the mass of 0.5 moles of sodium hydroxide, NaOH? (Na = 23, O = 16, H = 1)

Step 1: Mr of NaOH = 23 + 16 + 1 = 40
Step 2: mass = moles × Mr = 0.5 × 40 = 20 g
Answer: 20 g
Exam Tip
Always calculate Mr first before using the moles formula. Write it out clearly to avoid silly errors.
Percentage Composition
% mass of element = (total Ar of element in formula ÷ Mr of compound) × 100
Worked Example 5

Calculate the percentage of nitrogen in ammonium nitrate, NH₄NO₃. (N = 14, H = 1, O = 16)

Step 1: Mr of NH₄NO₃ = 14 + 4(1) + 14 + 3(16) = 14 + 4 + 14 + 48 = 80
Step 2: Total mass of N = 2 × 14 = 28
Step 3: % N = (28 ÷ 80) × 100 = 35%
Answer: 35% nitrogen
Empirical Formula

The empirical formula is the simplest whole number ratio of atoms of each element in a compound.

Steps

  1. Write the mass (or percentage) of each element
  2. Divide each by the Ar of that element (gives moles)
  3. Divide all values by the smallest value
  4. If needed, multiply to get whole numbers
Worked Example 6

A compound contains 40% calcium, 12% carbon, and 48% oxygen. Find its empirical formula. (Ca = 40, C = 12, O = 16)

Step 1: Divide by Ar:
Ca: 40 ÷ 40 = 1
C: 12 ÷ 12 = 1
O: 48 ÷ 16 = 3
Step 2: Divide by smallest (1): Ca = 1, C = 1, O = 3
Empirical formula: CaCO₃
Reacting Masses Calculations

Method

  1. Write the balanced equation
  2. Calculate moles of the substance you know
  3. Use the mole ratio from the equation to find moles of the substance you want
  4. Convert moles back to mass
Worked Example 7

What mass of carbon dioxide is produced when 10 g of calcium carbonate decomposes?
CaCO₃ → CaO + CO₂
(Ca = 40, C = 12, O = 16)

Step 1: Mr of CaCO₃ = 40 + 12 + 48 = 100
Step 2: Moles of CaCO₃ = 10 ÷ 100 = 0.1 mol
Step 3: Ratio CaCO₃ : CO₂ = 1 : 1, so moles of CO₂ = 0.1 mol
Step 4: Mr of CO₂ = 12 + 32 = 44
Step 5: Mass of CO₂ = 0.1 × 44 = 4.4 g
Answer: 4.4 g of CO₂
Concentration of Solutions
Concentration (mol/dm³) = moles ÷ volume (dm³)

Concentration (g/dm³) = mass (g) ÷ volume (dm³)

1 dm³ = 1000 cm³ | To convert cm³ to dm³: divide by 1000
Worked Example 8

4 g of NaOH is dissolved in 500 cm³ of water. Calculate the concentration in mol/dm³. (Na = 23, O = 16, H = 1)

Step 1: Mr of NaOH = 23 + 16 + 1 = 40
Step 2: Moles = 4 ÷ 40 = 0.1 mol
Step 3: Volume = 500 cm³ = 500 ÷ 1000 = 0.5 dm³
Step 4: Concentration = 0.1 ÷ 0.5 = 0.2 mol/dm³
Answer: 0.2 mol/dm³
Common Mistake
Forgetting to convert cm³ to dm³ before calculating concentration. Always divide by 1000!
Titration Calculations

Titration Method

  1. Measure a known volume of alkali into a conical flask using a pipette
  2. Add a few drops of indicator
  3. Add acid from a burette until the indicator changes colour (end point)
  4. Record the volume of acid used (titre)
  5. Repeat until concordant results (within 0.10 cm³)
Required Practical
Titration of HCl with NaOH: Use a 25.00 cm³ pipette for NaOH, phenolphthalein indicator, and a burette for HCl. Calculate the mean titre from concordant results (ignore anomalous results).

Titration Calculation Steps

  1. Calculate moles of the substance you know: moles = concentration × volume
  2. Use the mole ratio from the balanced equation
  3. Calculate the unknown concentration or volume
Worked Example 9

25.0 cm³ of 0.1 mol/dm³ NaOH is neutralised by 20.0 cm³ of HCl. Find the concentration of HCl.
NaOH + HCl → NaCl + H₂O

Step 1: Moles NaOH = 0.1 × (25.0 / 1000) = 0.1 × 0.025 = 0.0025 mol
Step 2: Ratio NaOH : HCl = 1 : 1, so moles HCl = 0.0025 mol
Step 3: Concentration HCl = 0.0025 ÷ (20.0 / 1000) = 0.0025 ÷ 0.02 = 0.125 mol/dm³
Answer: 0.125 mol/dm³
Yield and Atom Economy

Percentage Yield

% yield = (actual yield ÷ theoretical yield) × 100

Yield is always less than 100% because of: incomplete reactions, side reactions, loss during transfer/filtration/evaporation.

Atom Economy

% atom economy = (Mr of desired product ÷ total Mr of all products) × 100

High atom economy = less waste. Addition reactions have 100% atom economy. Industry prefers high atom economy for cost and environmental reasons.

Worked Example 10

A student expected to make 8.0 g of MgO but only obtained 6.4 g. Calculate the percentage yield.

Step 1: % yield = (actual ÷ theoretical) × 100
Step 2: = (6.4 ÷ 8.0) × 100 = 80%
Answer: 80%
Exam Tip
Percentage yield can never be greater than 100%. If your answer is above 100%, check your calculation.
Molar Volume of Gases

At room temperature and pressure (RTP) — 20 °C and 1 atmosphere — one mole of any gas occupies 24 dm³ (24 000 cm³).

volume of gas (dm³) = moles × 24

moles of gas = volume (dm³) ÷ 24

volume of gas (cm³) = moles × 24 000

moles of gas = volume (cm³) ÷ 24 000
Worked Example

What volume (in cm³) does 0.25 mol of carbon dioxide occupy at RTP?

Step 1: volume = moles × 24 000 cm³
Step 2: volume = 0.25 × 24 000 = 6000 cm³
Answer: 6000 cm³ (or 6 dm³)
Worked Example

What mass of magnesium is needed to produce 480 cm³ of hydrogen at RTP?
Mg + 2HCl → MgCl₂ + H₂ (Mg = 24)

Step 1: Moles of H₂ = 480 ÷ 24 000 = 0.02 mol
Step 2: Ratio Mg : H₂ = 1 : 1, so moles of Mg = 0.02 mol
Step 3: Mass of Mg = 0.02 × 24 = 0.48 g
Answer: 0.48 g
Exam Tip
The 24 dm³ value only applies at RTP. If the question states different conditions, you may need to use the gas law equations from the Gas Laws topic instead.
Crude Oil and Hydrocarbons

Crude oil is a fossil fuel formed from the remains of ancient marine organisms over millions of years. It is a mixture of hydrocarbons (compounds containing only hydrogen and carbon).

Fractional Distillation

Crude oil is separated into fractions by fractional distillation:

  1. Crude oil is heated until it evaporates
  2. Vapours enter the fractionating column (hot at bottom, cool at top)
  3. Different fractions condense at different heights based on their boiling points
  4. Shorter chain hydrocarbons rise higher (lower boiling point)

Trends in Hydrocarbons

PropertyShort chainsLong chains
Boiling pointLowHigh
ViscosityRunnyThick/viscous
FlammabilityMore flammableLess flammable
ColourLighterDarker

Uses of Fractions

  • Gases (LPG): heating, cooking
  • Petrol/gasoline: fuel for cars
  • Kerosene: jet fuel
  • Diesel: fuel for lorries, buses
  • Fuel oil: ships, power stations
  • Bitumen: roads, roofing
Alkanes

Alkanes are a family of saturated hydrocarbons (all single bonds, no double bonds).

General formula: CnH2n+2

First Four Alkanes

NameFormulaStructure
MethaneCH₄1 carbon
EthaneC₂H₆2 carbons
PropaneC₃H₈3 carbons
ButaneC₄H₁₀4 carbons

Combustion of Alkanes

Complete combustion: hydrocarbon + O₂ → CO₂ + H₂O
Incomplete combustion: produces CO (carbon monoxide) or C (soot) instead

Complete combustion requires plenty of oxygen. Incomplete combustion occurs with limited oxygen and produces toxic carbon monoxide and/or soot (carbon particles).

Common Mistake
Confusing alkanes and alkenes. Alkanes have ALL single bonds and are saturated. They do NOT decolourise bromine water.
Alkenes

Alkenes are unsaturated hydrocarbons containing at least one carbon-carbon double bond (C=C).

General formula: CnH2n

First Three Alkenes

NameFormula
EtheneC₂H₄
PropeneC₃H₆
ButeneC₄H₈

Test for Alkenes

Add bromine water (orange/brown). If it decolourises (turns colourless), an alkene (C=C double bond) is present. This is an addition reaction.

Addition Reactions

  • + Bromine: ethene + Br₂ → dibromoethane (test for unsaturation)
  • + Hydrogen: ethene + H₂ → ethane (hydrogenation, using a nickel catalyst)
  • + Water (steam): ethene + H₂O → ethanol (hydration, using phosphoric acid catalyst)
Quick Check

How can you distinguish between ethane and ethene using a simple chemical test?

Add bromine water to each.
Ethene will decolourise the bromine water (orange to colourless) because of the C=C double bond.
Ethane will not react — the bromine water stays orange.
Polymers

Addition polymerisation: many small alkene molecules (monomers) join together to form a long chain (polymer). The double bond opens up to form single bonds linking the monomers.

n C₂H₄ → -(CH₂-CH₂)-n
(many ethene monomers → poly(ethene))

Common Polymers and Uses

MonomerPolymerUses
EthenePoly(ethene) / PolythenePlastic bags, bottles
PropenePoly(propene)Ropes, crates, carpets
ChloroethenePVCPipes, window frames, clothing
StyrenePolystyrenePackaging, insulation

Environmental Issues

  • Most polymers are non-biodegradable — they persist in the environment for hundreds of years
  • Burning plastics releases toxic gases (e.g. HCl from PVC)
  • Plastics in oceans harm marine wildlife
  • Solutions: recycling, developing biodegradable polymers, reducing plastic use
Exam Tip
To identify the monomer from a polymer: look for the repeating unit, then add a C=C double bond back between the two carbons in the backbone.
Cracking

Cracking is the process of breaking down long-chain hydrocarbons into shorter, more useful molecules. It produces alkanes (for fuels) and alkenes (for making polymers and other chemicals).

Why Is Cracking Needed?

  • Fractional distillation produces more long-chain fractions than there is demand for
  • There is high demand for short-chain fuels (petrol) and alkenes (for polymers)
  • Cracking converts surplus long-chain molecules into these high-demand products

Thermal Cracking

  • Carried out at high temperatures (700-1000 °C) and high pressures
  • Produces a high proportion of alkenes

Catalytic Cracking

  • Uses a hot catalyst (e.g. zeolite or aluminium oxide) at about 500 °C
  • Lower temperature than thermal cracking
  • Produces more branched alkanes and aromatic hydrocarbons (used in fuels)

Example

C₁₀H₂₂ → C₈H₁₈ + C₂H₄
(decane → octane + ethene)

The products always include at least one alkene (with a C=C double bond). You can verify cracking has occurred by testing the products with bromine water — it will decolourise if alkenes are present.

Exam Tip
In cracking equations, check that the total number of carbon and hydrogen atoms balances on both sides. The products must include at least one alkene.
Functional Groups and Homologous Series

A homologous series is a family of compounds with the same functional group, the same general formula, and similar chemical properties. Each member differs by CH₂ from the next.

Properties of a Homologous Series

  • Same general formula
  • Same functional group — determines chemical properties
  • Similar chemical properties
  • Gradual change in physical properties (e.g. boiling points increase as chain length increases)
  • Each member differs from the next by CH₂

Key Homologous Series

SeriesFunctional GroupGeneral FormulaExampleSuffix
AlkanesC-C single bonds onlyCnH2n+2Methane (CH₄)-ane
AlkenesC=C double bondCnH2nEthene (C₂H₄)-ene
Alcohols-OH (hydroxyl)CnH2n+1OHEthanol (C₂H₅OH)-ol
Carboxylic acids-COOH (carboxyl)CnH2n+1COOHEthanoic acid (CH₃COOH)-anoic acid
Esters-COO- (ester link)Ethyl ethanoate-yl -anoate

Alcohols

Alcohols contain the -OH functional group. The first three are methanol (CH₃OH), ethanol (C₂H₅OH), and propanol (C₃H₇OH).

  • Dissolve in water to form neutral solutions
  • React with sodium to produce hydrogen
  • Burn in air to produce CO₂ + H₂O (used as fuels)
  • Used as solvents and in alcoholic drinks (ethanol)

Carboxylic Acids

Carboxylic acids contain the -COOH functional group. They are weak acids (only partially ionised in water).

  • React with metals: e.g. 2CH₃COOH + Mg → (CH₃COO)₂Mg + H₂
  • React with carbonates: e.g. 2CH₃COOH + Na₂CO₃ → 2CH₃COONa + H₂O + CO₂
  • React with alcohols to form esters (see below)
  • Examples: methanoic acid (HCOOH), ethanoic acid (CH₃COOH — found in vinegar)

Esters

Esters are formed when a carboxylic acid reacts with an alcohol in the presence of an acid catalyst (e.g. concentrated sulfuric acid). This is a condensation reaction (water is also produced).

carboxylic acid + alcohol ⇌ ester + water

CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O
(ethanoic acid + ethanol ⇌ ethyl ethanoate + water)
  • Esters have fruity/sweet smells
  • Used in flavourings, perfumes, and solvents
Exam Tip
To name an ester: the first part comes from the alcohol (e.g. ethyl from ethanol), the second part from the acid (e.g. ethanoate from ethanoic acid). So ethanol + ethanoic acid = ethyl ethanoate.
Fermentation and Making Ethanol

There are two methods for producing ethanol:

1. Fermentation

Fermentation uses yeast enzymes to convert sugars (glucose) into ethanol and carbon dioxide:

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
(glucose → ethanol + carbon dioxide)

Conditions required:

  • Temperature of about 30-40 °C (optimum for yeast enzymes)
  • Anaerobic conditions (no oxygen — otherwise ethanol is oxidised to ethanoic acid)
  • Yeast as a biological catalyst

Advantages: uses renewable sugar crops, low temperature, low energy cost.

Disadvantages: slow process, produces dilute ethanol (needs distillation to concentrate), batch process.

2. Hydration of Ethene

C₂H₄ + H₂O → C₂H₅OH
(ethene + steam → ethanol)

Conditions: high temperature (300 °C), high pressure (60-70 atm), phosphoric acid catalyst.

Advantages: fast, continuous process, produces pure ethanol.

Disadvantages: uses non-renewable crude oil (ethene from cracking), high energy cost.

FeatureFermentationHydration of Ethene
Raw materialSugar (renewable)Ethene from crude oil (non-renewable)
RateSlow (batch process)Fast (continuous process)
PurityImpure (needs distillation)Pure ethanol
Temperature~35 °C~300 °C
Atom economyLower (CO₂ by-product)100% (addition reaction)
Common Mistake
Saying fermentation uses "heat" or "high temperatures" — it uses warm temperatures (about 35 °C). Too hot would denature the yeast enzymes.
Addition vs Condensation Polymerisation

Addition Polymerisation (Recap)

  • Monomers must have a C=C double bond (alkenes)
  • The double bond opens up and monomers join together
  • Only one product (the polymer) — no by-product
  • 100% atom economy
n CH₂=CH₂ → -(CH₂-CH₂)-n

Condensation Polymerisation

  • Monomers have two functional groups (one at each end of the molecule)
  • Monomers join together with the loss of a small molecule (usually water, H₂O)
  • Two products: the polymer and the small molecule
  • Examples: polyesters (from dicarboxylic acid + diol), polyamides/nylon (from dicarboxylic acid + diamine), proteins (from amino acids)
FeatureAddition PolymerisationCondensation Polymerisation
Monomer requirementC=C double bondTwo functional groups per monomer
Number of productsOne (polymer only)Two (polymer + small molecule, e.g. H₂O)
Atom economy100%Less than 100%
Example polymersPoly(ethene), PVC, polystyrenePolyester, nylon, proteins
Bond type in polymerC-C backbone onlyContains ester links (-COO-) or amide links (-CONH-)
Exam Tip
You can identify condensation polymers because their backbone contains atoms other than just carbon (e.g. oxygen or nitrogen in the chain). Addition polymers have a carbon-only backbone.
The Atmosphere

Current Composition of the Atmosphere

  • Nitrogen: ~78%
  • Oxygen: ~21%
  • Argon: ~0.9%
  • Carbon dioxide: ~0.04%
  • Plus small amounts of water vapour and other gases

Evolution of Earth's Atmosphere

  1. Early atmosphere (4 billion years ago): mainly CO₂ and water vapour from volcanic activity. Little or no oxygen. Similar to Mars and Venus today.
  2. Water vapour condensed to form oceans. CO₂ dissolved in the oceans.
  3. Photosynthetic organisms (cyanobacteria, then algae and plants) evolved and produced oxygen:
    6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
  4. Oxygen built up, CO₂ decreased. Marine organisms locked CO₂ into shells (formed limestone/chalk). Dead organisms formed fossil fuels over millions of years.

Greenhouse Effect and Climate Change

Greenhouse gases (CO₂, methane, water vapour) absorb infrared radiation re-emitted from Earth's surface and re-radiate it in all directions, warming the atmosphere.

Human activities increasing greenhouse gases: burning fossil fuels (CO₂), deforestation (less CO₂ absorbed), agriculture and landfill (methane).

Consequences: rising global temperatures, melting ice caps, rising sea levels, extreme weather, habitat loss.

Common Mistake
Confusing the greenhouse effect with the ozone hole. They are different issues! The greenhouse effect is about heat being trapped. The ozone hole is about UV radiation. Do not mix them up in exam answers.
Water Treatment and Testing for Gases

Water Treatment

  1. Sedimentation: large particles settle out
  2. Filtration: smaller particles removed by passing through sand beds
  3. Chlorination: chlorine added to kill bacteria and make water safe to drink

Distillation can produce pure water but is too expensive and energy-intensive for large-scale use.

Testing for Gases

GasTestPositive Result
Hydrogen (H₂)Hold a burning splint to the gasSqueaky pop
Oxygen (O₂)Hold a glowing splint in the gasSplint relights
Carbon dioxide (CO₂)Bubble through limewaterLimewater turns milky/cloudy
Chlorine (Cl₂)Hold damp litmus paper in the gasLitmus paper is bleached white
Required Practical
Be able to carry out and describe the tests for hydrogen, oxygen, carbon dioxide, and chlorine. Know the positive result for each test.
Quick Check

A gas is produced when zinc reacts with hydrochloric acid. Name the gas and describe how you would test for it.

The gas is hydrogen.
Test: hold a burning splint near the mouth of the test tube.
Positive result: a squeaky pop is heard.
Required Practicals Summary
PracticalKey Points
Titration (acid-alkali)Pipette for fixed volume, burette for variable volume, concordant results, correct indicator choice
Rates of reactionDisappearing cross (sodium thiosulfate + HCl) or gas collection (Mg + HCl). Control variables, take repeat readings.
Electrolysis of copper sulfateCopper electrodes, measure mass change at each electrode, copper deposits at cathode
Making a salt (neutralisation)Add excess insoluble base to acid, filter, evaporate filtrate slowly to crystallise
Gas testsH₂ (squeaky pop), O₂ (relights splint), CO₂ (limewater milky), Cl₂ (bleaches litmus)
Flame testsClean nichrome wire in HCl, dip in sample, hold in Bunsen flame. Li = red, Na = yellow, K = lilac, Ca = orange-red, Cu = blue-green
Exam Tip
For practical questions, always mention: the equipment used, what you measure, what you keep the same (control variables), and how you ensure accuracy (repeats, concordant results).
Balancing Equations Practice

Balance each equation. Click to reveal the answer.

1. Fe + O₂ → Fe₂O₃

4Fe + 3O₂ → 2Fe₂O₃

2. Na + H₂O → NaOH + H₂

2Na + 2H₂O → 2NaOH + H₂

3. CH₄ + O₂ → CO₂ + H₂O

CH₄ + 2O₂ → CO₂ + 2H₂O

4. Al + HCl → AlCl₃ + H₂

2Al + 6HCl → 2AlCl₃ + 3H₂

5. C₂H₆ + O₂ → CO₂ + H₂O

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Command Words
Command WordWhat It Means
StateGive a brief, factual answer — no explanation needed
DescribeSay what happens, give an account of something
ExplainGive reasons WHY something happens, using scientific knowledge
CompareIdentify similarities AND differences
SuggestApply your knowledge to an unfamiliar situation (no single right answer)
CalculateUse numbers and show your working clearly
EvaluateWeigh up evidence and reach a supported conclusion
JustifyGive reasons for your answer, backed by evidence or data
DeduceDraw a conclusion from the information given
PredictUse patterns or trends to give an expected outcome
Exam Tip
If the question says "explain", you MUST give reasons. Just describing what happens without saying why will lose marks. Look at the marks available — 2 marks usually means 2 separate points.
Common Mistakes to Avoid
  1. Saying ionic compounds contain "molecules" — they form giant ionic lattices, not molecules.
  2. Saying "covalent bonds are weak" — the bonds are strong! It is the intermolecular forces that are weak in simple molecules.
  3. Changing subscript numbers when balancing — only change the big numbers (coefficients) in front of formulae.
  4. Forgetting to convert cm³ to dm³ — divide by 1000 before using concentration formulae.
  5. Saying temperature "gives particles more energy to react" — say that more particles exceed the activation energy.
  6. Mixing up Group 1 and Group 7 reactivity trends — metals get more reactive going down, halogens get less reactive.
  7. Confusing oxidation and reduction — remember OIL RIG (Oxidation Is Loss, Reduction Is Gain of electrons).
  8. Writing "electrons are shared" in ionic bonding — in ionic bonding, electrons are transferred, not shared.
  9. Saying a catalyst "gives energy" to a reaction — a catalyst lowers the activation energy by providing an alternative pathway.
  10. Confusing greenhouse effect with ozone layer depletion — these are completely separate environmental issues.
  11. Forgetting state symbols — many CCEA mark schemes require (s), (l), (g), (aq).
  12. Saying "atoms want to have a full outer shell" — atoms do not have desires. Say atoms are "more stable" with a full outer shell.
Key Terms Glossary
Atom
The smallest part of an element that can take part in a chemical reaction.
Element
A substance made of only one type of atom. Cannot be broken down chemically.
Compound
A substance made of two or more different elements chemically bonded together.
Mixture
Two or more substances not chemically bonded. Can be separated by physical methods.
Isotope
Atoms of the same element with the same number of protons but different numbers of neutrons.
Ion
A charged particle formed when an atom gains or loses electrons.
Ionic bond
Electrostatic attraction between oppositely charged ions formed by electron transfer.
Covalent bond
A shared pair of electrons between two non-metal atoms.
Metallic bond
Electrostatic attraction between positive metal ions and delocalised electrons.
Electrolysis
Decomposition of a compound using electricity. The compound must be molten or in solution.
Anode
The positive electrode in electrolysis. Anions are attracted here and oxidised.
Cathode
The negative electrode in electrolysis. Cations are attracted here and reduced.
Oxidation
Loss of electrons, or gain of oxygen.
Reduction
Gain of electrons, or loss of oxygen.
Catalyst
A substance that increases the rate of reaction without being used up. Provides an alternative pathway with lower activation energy.
Activation energy
The minimum energy required for a reaction to occur.
Exothermic
A reaction that transfers energy to the surroundings (temperature increases).
Endothermic
A reaction that takes in energy from the surroundings (temperature decreases).
Mole
The amount of substance containing 6.02 x 10^23 particles (Avogadro's number).
Relative formula mass (Mr)
The sum of the relative atomic masses of all atoms in a formula.
Empirical formula
The simplest whole number ratio of atoms of each element in a compound.
Concentration
The amount of solute dissolved in a given volume of solution (mol/dm³ or g/dm³).
Hydrocarbon
A compound containing only hydrogen and carbon atoms.
Saturated
A molecule with only single covalent bonds between carbon atoms (e.g. alkanes).
Unsaturated
A molecule containing at least one C=C double bond (e.g. alkenes).
Polymer
A large molecule made by joining many small monomer molecules together.
Monomer
A small molecule that joins with others to form a polymer.
Fractional distillation
Separation of a mixture based on different boiling points of the components.
Greenhouse gas
A gas (CO₂, CH₄, H₂O) that absorbs and re-emits infrared radiation, warming the atmosphere.
Atom economy
The percentage of reactant atoms that form the desired product.
Displacement reaction
A more reactive element takes the place of a less reactive element in a compound.
Precipitate
An insoluble solid formed when two solutions are mixed.
Titre
The volume of solution added from the burette during a titration.
Reversible reaction
A reaction that can proceed in both directions; products can reform reactants. Shown by the ⇌ symbol.
Dynamic equilibrium
When the rates of the forward and reverse reactions are equal and concentrations remain constant, in a closed system.
Le Chatelier's principle
If a system at equilibrium is disturbed, the equilibrium shifts to oppose the change.
Redox reaction
A reaction involving both oxidation and reduction occurring simultaneously.
Oxidation state
A number assigned to an element indicating the degree of oxidation; tracks electron transfer in redox reactions.
Galvanising
Coating iron or steel with zinc to prevent rusting by barrier protection and sacrificial protection.
Sacrificial protection
Attaching a more reactive metal to iron so it corrodes instead of the iron.
Alcohol
An organic compound containing the -OH functional group. General formula CₙH₂ₙ₊₁OH.
Carboxylic acid
An organic compound containing the -COOH functional group. A weak acid.
Ester
An organic compound formed from a carboxylic acid and an alcohol; has a fruity smell.
Fermentation
The conversion of sugar to ethanol and carbon dioxide using yeast enzymes under anaerobic conditions.
Cracking
Breaking down long-chain hydrocarbons into shorter, more useful molecules using heat and/or a catalyst.
Condensation polymerisation
Polymerisation where monomers join together with the loss of a small molecule (e.g. water).
Homologous series
A family of compounds with the same functional group, same general formula, and similar chemical properties.
Functional group
The atom or group of atoms responsible for the characteristic reactions of a compound.
Molar volume
The volume occupied by one mole of any gas. At RTP this is 24 dm³ (24 000 cm³).
Cryolite
Na₃AlF₆; used to lower the melting point of aluminium oxide in the extraction of aluminium.
Electroplating
Using electrolysis to coat an object with a thin layer of metal for appearance or protection.
Exam Tips
Exam Tip
Read the question twice. Underline key words (explain, describe, calculate, state) and the number of marks. Each mark usually requires a separate point.
Exam Tip
Show all working in calculations. Even if your final answer is wrong, you can pick up method marks. Always include units in your answer.
Exam Tip
Use scientific terminology. Say "delocalised electrons" not "free electrons floating around". Say "electrostatic attraction" not "they stick together".
Exam Tip
For 6-mark questions: plan your answer, use paragraphs, include scientific vocabulary, and ensure you cover all points. Quality of written communication is assessed.
Exam Tip
Graph questions: always read axis labels and units. Calculate gradient using two clear points far apart. Include units for the gradient.
Exam Tip
Practical questions: name specific equipment (measuring cylinder, not "container"). Describe how you would make the test fair (control variables).
Exam Tip
Time management: roughly 1 minute per mark. Do not spend 10 minutes on a 2-mark question. If stuck, move on and come back.
Key Formulas
Relative formula mass:
Mr = sum of all Ar values in the formula
Moles:
moles = mass (g) ÷ Mr
mass = moles × Mr
Percentage composition:
% mass = (total Ar of element ÷ Mr) × 100
Concentration (mol/dm³):
concentration = moles ÷ volume (dm³)
Concentration (g/dm³):
concentration = mass (g) ÷ volume (dm³)
Percentage yield:
% yield = (actual yield ÷ theoretical yield) × 100
Atom economy:
% atom economy = (Mr of desired product ÷ total Mr of all products) × 100
Energy change (bond energies):
Energy change = energy to break bonds − energy released making bonds
Molar volume of gas (at RTP):
volume (dm³) = moles × 24
moles = volume (dm³) ÷ 24
Boyle's Law (constant T):
P₁V₁ = P₂V₂
Charles's Law (constant P):
V₁/T₁ = V₂/T₂ (T in Kelvin)
Pressure Law (constant V):
P₁/T₁ = P₂/T₂ (T in Kelvin)
Volume conversion:
1 dm³ = 1000 cm³ | cm³ ÷ 1000 = dm³
K = °C + 273
Quick Check

A solution has a concentration of 0.5 mol/dm³. 25 cm³ is used. How many moles is that?

Volume = 25 / 1000 = 0.025 dm³
Moles = 0.5 × 0.025 = 0.0125 mol
Quick Check

What is the Mr of sulfuric acid, H₂SO₄? (H = 1, S = 32, O = 16)

Mr = 2(1) + 32 + 4(16) = 2 + 32 + 64 = 98